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Schach [20]
2 years ago
7

Construct a model to show the movement of matter and energy from plants into other organisms. Show how mass and energy are conse

rved before and after each interaction. For example, the beginning substances before an interaction equal the ending substances, and vice versa.
I listed a student example I need something like the example but for photosynthesis asap I will give 100 points to whoever has the correct answer

Chemistry
1 answer:
ad-work [718]2 years ago
3 0

Plants obtain energy from the sun during photosynthesis and pass it along the food chain.

<h3>What is a model?</h3>

A model is a representation of reality. We use models to understand what the real situation of things is like.

Let us recall that plants are the producers in the ecosystem. Energy flow from plants to animals. Plants obtain energy via the reaction 6CO2 + 6H2O --->C6H12O6 + ATP. This energy is passed along the food chain as organisms feed on each other.

Learn more about models: brainly.com/question/14281845

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At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)&lt;---&gt;2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an
SOVA2 [1]

<u>Answer:</u> The equilibrium concentration of CO is 0.243 atm

<u>Explanation:</u>

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

                      Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)

<u>Initial:</u>                                                                  0.902

<u>At eqllm:</u>                            3x                           (0.902-3x)

The expression of K_p for above equation follows:

K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}

We are given:

K_p=19.9

Putting values in above equation, we get:

19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

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3 years ago
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Convert 150.0 g to mg.
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There are 1000 milligrams in a gram, so you can find the answer through multiplication: 150 • 1000

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