Answer:
16 m/s
Explanation:
First, find the displacement in the east direction.
x = (15 m/s sin 45°) (3600 s) + (18 m/s cos 5°) (3600 s)
x = 102,737 m
Next, find the displacement in the north direction.
y = (15 m/s cos 45°) (3600 s) + (18 m/s sin 5°) (3600 s)
y = 43,831 m
Find the magnitude of the displacement.
d = √(x² + y²)
d = √((102,737 m)² + (43,831 m)²)
d = 111,697 m
Finally, find the resultant velocity.
v = d / t
v = (111,697 m) / (7200 s)
v = 15.5 m/s
Rounded to the nearest whole number, the resultant velocity is 16 m/s.
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So, the temperature of a wave that has a wavelength of 5 m is ![\boxed{\sf{5.796 \times 10^{-4} \: K}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7B5.796%20%5Ctimes%2010%5E%7B-4%7D%20%5C%3A%20K%7D%7D%20)
<h3>Introduction</h3>
Hi ! Here, I will help you to explain about The relationship between temperature and electromagnetic wavelength uses the principle of Wien's Constant. According to Wien, <u>if we multiply temperature with the electromagnetic wavelengths will always got the same number (constant)</u>. Therefore, The relationship is expressed in this equation :
![\boxed{\sf{\bold{C = \lambda_{max} \times T}}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7B%5Cbold%7BC%20%3D%20%5Clambda_%7Bmax%7D%20%5Ctimes%20T%7D%7D%7D%20)
With the following condition :
- C = Wien's constant ≈
![\sf{2.898 \times 10^{-3} \: m.K}](https://tex.z-dn.net/?f=%20%5Csf%7B2.898%20%5Ctimes%2010%5E%7B-3%7D%20%5C%3A%20m.K%7D%20)
= wave at its longest point (m) - T = absolute temperature (K)
<h3>Problem Solving</h3>
We know that :
- C = Wien's constant ≈
![\sf{2.898 \times 10^{-3} \: m.K}](https://tex.z-dn.net/?f=%20%5Csf%7B2.898%20%5Ctimes%2010%5E%7B-3%7D%20%5C%3A%20m.K%7D%20)
= wave at its longest point = 5 m
What was asked :
- T = absolute temperature = ... K
Step by step :
![\sf{C = \lambda_{max} \times T}](https://tex.z-dn.net/?f=%20%5Csf%7BC%20%3D%20%5Clambda_%7Bmax%7D%20%5Ctimes%20T%7D%20)
![\sf{2.898 \times 10^{-3} = 5 \times T}](https://tex.z-dn.net/?f=%20%5Csf%7B2.898%20%5Ctimes%2010%5E%7B-3%7D%20%3D%205%20%5Ctimes%20T%7D%20)
![\sf{T = \frac{2.898 \times 10^{-3}}{5}}](https://tex.z-dn.net/?f=%20%5Csf%7BT%20%3D%20%5Cfrac%7B2.898%20%5Ctimes%2010%5E%7B-3%7D%7D%7B5%7D%7D%20)
![\sf{T = \frac{2.898 \times 10^{-3}}{5}}](https://tex.z-dn.net/?f=%20%5Csf%7BT%20%3D%20%5Cfrac%7B2.898%20%5Ctimes%2010%5E%7B-3%7D%7D%7B5%7D%7D%20)
![\sf{T = 0.5796 \times 10^{-3}}](https://tex.z-dn.net/?f=%20%5Csf%7BT%20%3D%200.5796%20%5Ctimes%2010%5E%7B-3%7D%7D%20)
![\boxed{\sf{T = 5.796 \times 10^{-4} \: K}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7BT%20%3D%205.796%20%5Ctimes%2010%5E%7B-4%7D%20%5C%3A%20K%7D%7D%20)
<h3>Conclusion :</h3>
So, the temperature of a wave that has a wavelength of 5 m is ![\boxed{\sf{5.796 \times 10^{-4} \: K}}](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Csf%7B5.796%20%5Ctimes%2010%5E%7B-4%7D%20%5C%3A%20K%7D%7D%20)
You did not provide the options. However, the options are
I = 6.0, R= 4.0 ohms
I = 9.0, R= 2.0ohms
I = 3.0, R= 2.0ohms
I = 8.0, R= 8.0 ohms
Answer:
The order of the resistors from the highest to the lowest is:
I = 8.0, R= 8.0 ohms
I = 6.0, R= 4.0 ohms
I = 9.0, R= 2.0ohms
I = 3.0, R= 2.0 ohms
Explanation:
ohm's law states that voltage across a conductor is directly proportional to the current flowing through it. V = IR
Based on this formula, the voltages in each of the resistors are calculated below from the highest to the lowest
V = 8 * 8 =64 volts
V = 6 * 4 =24 volts
V = 9 * 2 =18 volts
V = 3 * 2 =6 volts
Answer:
Young's modulus of this tendon is
.
Explanation:
Given that,
Length of the tendon, l = 19 cm
It is stretched by 4.5 mm, ![\Delta l=4.5\ mm](https://tex.z-dn.net/?f=%5CDelta%20l%3D4.5%5C%20mm)
Force, F = 11.3 N
Average diameter, d = 8.2 mm
Radius, r = 4.1 mm
The formula of Young's modulus of this tendon is given by :
![Y=\dfrac{Fl}{\Delta l A}\\\\Y=\dfrac{11.3\times 0.19}{4.5\times 10^{-3}\times \pi (4.1\times 10^{-3})^2}\\\\Y=9.03\times 10^6\ N/m^2](https://tex.z-dn.net/?f=Y%3D%5Cdfrac%7BFl%7D%7B%5CDelta%20l%20A%7D%5C%5C%5C%5CY%3D%5Cdfrac%7B11.3%5Ctimes%200.19%7D%7B4.5%5Ctimes%2010%5E%7B-3%7D%5Ctimes%20%5Cpi%20%284.1%5Ctimes%2010%5E%7B-3%7D%29%5E2%7D%5C%5C%5C%5CY%3D9.03%5Ctimes%2010%5E6%5C%20N%2Fm%5E2)
So, the Young's modulus of this tendon is
. Hence, this is the required solution.