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Naily [24]
3 years ago
14

What does the term “retroperitoneal” mean in the terms of the location of the kidneys ?

Physics
1 answer:
lakkis [162]3 years ago
5 0

Answer:

"Retroperitoneal" refers to the back of the peritoneum, the membrane that lines the anatomical space in the abdominal cavity. Kidney stones may cause pain to the organs within the retroperitoneal space. A diagram of the aorta, a retroperitoneal structure.

Explanation:

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The volume of water in a measuring cylinder is 50 ml. When a piece of stone is immersed
Sergio039 [100]
Volume = 873 - 50 = 723 cm^3
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3 years ago
Copernicus incorrectly assumed that the planets?
hammer [34]
Nicholas Copernicus correctly assumed that the planets revolved around the sun but he incorrectly assumed that the planets followed a perfect circle orbit around the sun. It was later on discovered by Johannes Kepler that the planets moved around the sun following an elliptical orbit.
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3 years ago
A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I
vodka [1.7K]

Answer:

a = 603.59 m/s^2

Explanation:

from the data given . the rate of change in magnetic field is as follow

\frac{dB}{dt} = 280 G/s = 280 \times 10^{-4} T/s

from the faraday's law of induction , the expression for the induced emf in region of radius r as follow

\epsilon = \frac{d \phi}{dt}

\int E.dl = \frac{d(BA)}{dt}

E(2\pi r)= \pi r^2 \frac{dB}{dt}

E = \frac{r}{2} \frac{dB}{dt}

electric field at point P_1 as follow

E = \frac{r}{2} \frac{dB}{dt}

E = \frac{1.5\times 10^{-2}}{2} 280 \times 10^{-4}

E = 6.3\times 10^{-6} V/m

from newton 2nd law of motion, the acceleration of proton is

F = ma

qE = ma

a = \frac{qE}{m}

a = \frac{1.6 \times 10^{-19} (6.3\times 10^{-6})}{1.67\times 10^{-27}}

a = 603.59 m/s^2

5 0
3 years ago
How can scientists study the inner structure of an atom?
Arturiano [62]
A microscope is one way
8 0
3 years ago
A painter stands a horizontal platform which has a mass of 20kg and is 5m long, the platform is suspended by two vertical ropes
Lerok [7]

Answer:

R = 715.4 N

L =  166.6 N

Explanation:

ASSUME the painter is standing right of center

Let L be the left rope tension

Let R be the right rope tension

Sum moments about the left end to zero. Assume CCW moment is positive

R[5] - 20(9.8)[5/2] - 70(9.8)[5/2 + 2] = 0

R = 715.4 N

Sum moments about the right end to zero

20(9.8)[5/2] + 70(9.8)[5/2 - 2] - L[5] = 0

L =  166.6 N

We can verify by summing vertical forces

116.6 + 715.4 - (70 + 20)(9.8) ?=? 0

                                             0 = 0  checks

If the assumption about which side of center the paint stood is incorrect, the only difference would be the values of L and R would be swapped.

5 0
3 years ago
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