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Wewaii [24]
3 years ago
12

if 6000j of energy is supplid to a machine to lift a load of 300N through a vvertical height of 1M calculatework out put​

Physics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

300J

Explanation:

Work done = Force x the distance travelled in the direction of the force

=300 x 1

=300J

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In a given concern, mass m₁ is M, mass m₂ is 3M. Initial speed for the mass m₁ and  m₂ will be u₁=5 and u₂=0 m/s respectively,

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The velocity of block A is found as;

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Hence, the final velocity of the block A will be 2.5 m/sec.

To learn more about the law of conservation of momentum, refer;

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The great astronomer of ancient times who summarized and improved...in a book now called The Almagest) is Ptolemy This is further explained below.

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Hello!

\large\boxed{KE = 50J}

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