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EleoNora [17]
2 years ago
10

How much money would be saved by turning off one 100.0-W lightbulb 3.0 h/day for 365 days if the

Physics
1 answer:
Pavlova-9 [17]2 years ago
3 0

Answer:

the money that would be saved is $13.14.

Explanation:

Given;

power consumed by the light bulb, P = 100 W = 0.1 kW

time of running the bulb, t = 3 hours for 365 days = 1,095 hours

cost rate of power consumption, C = $0.12 per kWh

Energy consumed by the light bulb for the given days;

E = Pt

E = 0.1 kW  x 1,095 hr

E = 109.5 kWh

Cost of energy consumed = 109.5 kWh   x   $0.12 / kWh

                                            = $13.14

Therefore, the money that would be saved is $13.14.

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A) the unstretched length of each elastic rope is 24m. The rope obeys hookes law. The vertical distance between P and Q is 35m.
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Explanation:

a) The rope obeys Hooke's law, so:

F = k Δx

The elastic energy in the rope is:

EE = ½ k Δx²

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EE = ½ F Δx

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x =  37.25

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Δx = 37.25 − 24

Δx = 13.25

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EE = ½ (3.7×10⁴ N) (13.25 m)

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Rounded to one significant figure, the height is 40 m.  So the claim is not justified.

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