Answer:
a) x_{cm} = m₂/ (m₁ + m₂) d
, b) x_{cm} = 52.97 pm
Explanation:
The expression for the center of mass is
= 1 / M ∑
Where M is the total masses, mI and xi are the mass and position of each element of the system.
Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon
x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)
Let's reduce the magnitudes to the SI system
m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg
m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg
d = 128 pm = 128 10⁻¹² m
The equation for the center of mass is
x_{cm} = m₂/ (m₁ + m₂) d
b) let's calculate the value
x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12
x_{cm} = 52.97 10⁻¹² m
x_{cm} = 52.97 pm
Answer: not be able to stop in time to miss the object
Explanation:
The phrase "Over-driving your headlights" means that a person is driving at such a speed that the vehicle's stopping distance is greater than the maximum viewable distance with the headlights on.
When this occurs, it will be impossible for the vehicle to stop moving in time to avoid an object viewed by the driver in the range of his headlights.
This is a <u>dangerous driving practice</u> and can be avoided by driving at <u>reduced speeds</u>.
The acceleration due to gravity at the Earth's surface is 9.8 m/s/s
<span>So a 2 kg object will accelerate at 9.8 m/s/s if it is dropped..... actually all dropped objects will accelerate at the same rate. </span>
<span>The force of gravity on the object is given by Newton's 2nd Law </span>
<span>F = m . a </span>
<span>F = 2 . 9.8 = 19.6 N </span>
<span>Now go to Mars , with a lower gravitational field strength. It only accelerates falling objects at 3.71 m/s/s </span>
<span>So the force of gravity on the object is F = 2 . 3.71 = 7.42 N </span>
<span>But the answer is (2) 2 kg, because the mass of the object stays the same and that is what you are asked for. </span>
<span>Someone was trying to be tricky.</span>
Answer:
2234.63
Explanation:
Work done per cycle by the engine is calculated as;

#Since volume doesn't change in the isochoric steps, there is no work done, hence:

#For an isothermal change of state(ideal gas):

#for the expansion process:



Hence, the engine does 2234.63J per second.