That the total energy of an isolated system remains constant and is said to be conserved over time
Answer:
675m
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 6m/s²
Time = 15s
Unknown:
Distance traveled by the body = ?
Solution:
To solve this problem; we use the expression;
S = ut + 
at²
Where u is the initial velocity
t is the time
a is the temperature
Insert the parameters and solve;
S = 0 x 15 + x 6 x 15²
S = 675m
The formula relating acceleration and angular velocity is:
a = ω^2 r
where a is acceleration, ω is angular velocity and r is
radius
But the angular velocity ω is constant all throughout the
disk therefore:
a1 / r1 = a2 / r2
So at points:
<span>r1 = 0.0130 m ->
a1 = 393 m/s^2</span>
<span>r2 = 0.0884 m ->
a2 = ?</span>
393 / 0.0130 = a2 / 0.0884
<span>a2 = 2,672.4 m/s^2</span>
Answer: X = 52,314.12 N
Explanation: Let X be the force the feet of the athlete exerts on the floor.
According to newton's third law of motion the floor gives an upward reaction based on the weight of the athlete and the barbell which is known as the normal reaction ( based on the mass of the athlete and the barbell)
Mass of athlete = 87kg, mass of barbell = 600/ hence total normal reaction from the floor = 87* 61.22/ 9.8 *9.8 = 52,200N.
The athlete lifts the barbell from rest thus making it initial velocity u=0, distance covered = S = 0.65m and the time taken = 1.3s
The acceleration of the barbell is gotten by using the equation of constant acceleration motion
S= ut + 1/2at²
But u = 0
S = 1/2at²
0.65 = 1/2 *a (1.3)²
0.65 = 1.69 * a/2
0.65 * 2 = 1.69 * a
a = 0.65 * 2/ 1.69
a = 0.77m/s²
According to newton's second law of motion
Resultant force = mass * acceleration
And resultant force in this case is
X - 52,200 = (87 + 61.22) * 0.77
X - 52,200 = 148.22 * 0.77
X - 52, 200 = 114.132
X = 114.132 + 52,200
X = 52,314.12 N
instantaneous speed of the car
