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suter [353]
2 years ago
5

A river 800m wide flows at the rate of 5km/h . A swimmer who can swim at 10km/h in still water wants to cross the river straight

.
Along what direction must he strike ?

Please solution with explanation
Physics
1 answer:
LuckyWell [14K]2 years ago
6 0

Answer:

At an angle of 30^{\circ}

Explanation:

Assume the river flows from East to West so for the swimmer to cross across it, assume he crosses it from West to East.

The resultant speed will be given by

R= \sqrt {10^{2}-5^{2}=\sqrt {75}\approx 8.66 km/h\\Direction=sin^{-1}\frac {5}{10}\approx 30^{\circ}

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The net gain in potential energy by the crate is 120 J.

<h3>What is potential energy?</h3>

Potential energy is the energy that an object has stored in it as a result of its position or condition. Potential energy exists in a stretched spring, a book held above your head, and a bicycle on top of a hill. The joule, which is represented by the letter "J," is the standard unit for calculating potential energy.

<h3 /><h3>Calculation:</h3>

We use the idea of potential energy, which is given by the equation,

PE = mgh

where,

m = mass of the crate

g = gravitational acceleration

h = height

Given,

mg = 40 N

L = 5 m

angle of inclination, ∅ = 37°

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h = 5 (sin 37°)

h = 5 (3/5)

h = 3 m

Put the values in the above formula,

PE = mgh

PE = 40 (3)

PE = 120 J

Therefore, the net gain in potential energy by the crate is 120 J.

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1 year ago
Difference between basic units and derived unit​
Molodets [167]

Answer:

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When Momentum is conserved it is called ________ .​
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Answer:

When Momentum is conserved it is called conservation of momentum

Explanation:

6 0
2 years ago
Read 2 more answers
ANSWER FAST!!!!
Amiraneli [1.4K]

Power = (voltage) x (current)

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4 0
3 years ago
If a sample emits 2000 counts per second when the detector is 1 meter from the sample, how many counts per second would be obser
Alona [7]

Answer:

<h2><em>6000 counts per second</em></h2>

Explanation:

If a sample emits 2000 counts per second when the detector is 1 meter from the sample, then;

2000 counts per second = 1 meter ... 1

In order to know the number of counts per second that would be observed when the detector is 3 meters from the sample, we will have;

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Solving the two expressions simultaneously for x we will have;

2000 counts per second = 1 meter

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Cross multiply to get x

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