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djverab [1.8K]
2 years ago
9

To test the hypothesis that the population mean mu=3. 6, a sample size n=14 yields a sample mean 4. 007 and sample standard devi

ation 0. 607. Calculate the p-value and choose the correct conclusion
Physics
1 answer:
PolarNik [594]2 years ago
5 0

The P value for the given data set is 25127. For finding P value, we have to must find the Z value.

<h3>How to get the z scores?</h3>

If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.

The Z value is calculated as;

Z = \dfrac{X - \mu}{\sigma})

Z = (X - μ) / σ

Z = (4.007 - 3.6) / 0.607

Z = 0.67051

The P value for the given data set is 25127.

Learn more about z-score here:

brainly.com/question/21262765

#SPJ1

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If two objects interact, the forces they impart on each other will be
Lady_Fox [76]
B) equal in magnitude but opposite direction
4 0
3 years ago
| A T-ball with a mass of 0.6 kg travels in the
r-ruslan [8.4K]

Answer:

|I|=6\ Kg.m/s

F=120\ N

Explanation:

Impulse and Momentum

They are similar concepts since they deal with the dynamics of objects having their status of motion changed by the sudden application of a force. The momentum at a given initial time is computed as

p_o=m.v_o

When a force is applied, the speed changes to v_1 and the new momentum is

p_1=m.v_1

The change of momentum is

\Delta p=p_1-p_0=m(v_1-v_o)

The impulse is equal to the change of momentum of an object and it's defined as the average net force applied times the time it takes to change the object's motion

I=F.t=\Delta p

Part 1

The T-ball initially travels at 10 m/s and then suddenly it's stopped by the glove. The final speed is zero, so

\Delta p=0.6\ Kg(0-10\ m/s)=-6\ Kg.m/s

The impulse is

I=\Delta p

I=-6\ Kg.m/s

The magnitude is

|I|=6\ Kg.m/s

Part 2

The force can be computed from the formula

I=F.t

The direction of the impulse the T-ball receives is opposite to the direction of the force exerted by the ball on the glove, thus I_b=6\ kg.m/s

\displaystyle F=\frac{I}{t}=\frac{6\ kg.m/s}{0.05\ s}

\boxed{F=120\ N}

7 0
3 years ago
What is the resistance ofa wire made of a material with resistivity of 3.2 x 10^-8 Ω.m if its length is 2.5 m and its diameter i
Katarina [22]

R = 0.407Ω.

The resistance  R of a particular conductor is related to the resistivity ρ of the material by  the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of ​​the material.

To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.

We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4.  Then:

R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]

R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²

R = 0.407Ω

5 0
3 years ago
A 1.0 kg block is placed against an ideal spring with spring constant 800 N/m and initially compressed 0.20 m. The spring and bl
densk [106]

Answer:

the release will be at 3.266 m distance

Explanation:

mass = 1 Kg

spring constant (k) = 800 N/m

initial compression = 0.20 m

θ = 30⁰

U= \dfrac{1}{2}kx^2\\U= \dfrac{1}{2}800\times 0.2^2\\U= 16 J

U=mgh\\h=\dfrac{U}{mg}\\h=\dfrac{16}{1 \times 9.8}\\h = 1.633m

d=\dfrac{h}{sin \theta}\\d=\dfrac{1.633}{sin 30}\\\\d= 3.266m

hence the release will be at 3.266 m distance.

5 0
3 years ago
CP Bang! A student sits atop a platform a distance h above the ground. He throws a large firecracker horizontally with a speed.
Firlakuza [10]

Answer:

 h = v₀ g / a

Explanation:

We can solve this problem using the kinematic equations. As they indicate that the air does not influence the vertical movement, we can find the time it takes for the body to reach the floor

          y = v_{oy} t - ½ g t²

The vertical start speed is zero

            t² = 2t / g

The horizontal document has an acceleration, with direction opposite to the speed therefore it is negative, the expression is

            x = v₀ₓ t - ½ a t²

Indicates that it reaches the same exit point x = 0

           v₀ₓ t = ½ a t2

           v₀ₓ = ½ a (2h / g)

           v₀ₓ = v₀

           h = v₀ g / a

7 0
3 years ago
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