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Reptile [31]
3 years ago
8

A 735 kg object and a 1.37×1012 kg are located 2.59×104 m away from each other. What is the force due to gravity between the two

objects?
Physics
1 answer:
antiseptic1488 [7]3 years ago
8 0

Answer:

Fg=1.02*10^-4 N

Explanation:

Fg=Gm1m2/r^2

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A group of organisms that is able to interbreed is called a
uranmaximum [27]

Answer:

D species

Explanation:

According to the most widely used species definition, the biological species concept, a species is a group of organisms that can potentially interbreed, or mate, with one another to produce viable, fertile offspring. In this definition, members of the same species must have the potential to interbreed.

8 0
3 years ago
What type of objects cannot pull to magmets
boyakko [2]

Answer:

brass, copper, zinc and aluminum, wood, glass, and plastic

Explanation:

7 0
3 years ago
Read 2 more answers
i learned that kinetic energy is energy when an object is actually moving not including the moving particles. i also learned tha
GaryK [48]

Answer:

Part of that kinetic energy created by moving of particles in object is transformed to heat that can be measured by thermometer.

Explanation:

By moving object creates kinematic energy, that is true. In object itself small particles are moving and creating kinetic energy as well. Part of that kinetic energy created by moving of particles in object is transformed to heat that can be measured by thermometer.

Same thing is that when you run or exercise your body temperature is raising(because of moving ).

When you sit your body does not raise temperature.

6 0
3 years ago
g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?
beks73 [17]

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

F = \sqrt{F_x^2 + F_y^2}

F = \sqrt{5.69^2 + 8^2}

F = \sqrt{32.3761 + 64}

F = \sqrt{96.3761}

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

4 0
3 years ago
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An air-filled pipe is found to have successive harmonics at 700 Hz , 900 Hz , and 1100 Hz . It is unknown whether harmonics belo
Artyom0805 [142]

Answer:

the length of the pipe is 0.85 m or 85 cm

Explanation:

Given the data in the question;

The successive harmonics are;  700 Hz , 900 Hz , and 1100 H

Now, for a closed pipe,

length of pipe (L) = λ/4

Harmonics; 1x, 3x, 5x, 7x, 9x, 11x

1100Hz - 900Hz = 200Hz

⇒ 2x = 200Hz

x = 100Hz ( fundamental frequency )

λ = V/f = 340 /100 = 3.4 m

Now

Length L = λ / 4

L = 3.4 / 4

L = 0.85 m or 85 cm

Therefore, the length of the pipe is 0.85 m or 85 cm

7 0
3 years ago
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