The definition is a nuclear reactor that generates more fissile material than it consumes.
On your list you can easily identify by knowing which is not a chemical change.
A physical change is a change not involving the material composition of the water. e.g. (melting, solidifying, evaporation). As long as the change does not change the molecular composition of the water which is H20 it is physical change.
Answer : The equilibrium concentration of T(g) is 0.5 M
Solution :
Let us assume that the equilibrium reaction be:
The given equilibrium reaction is,

The expression of
will be,
![K_c=\frac{[Z][X]^2}{[R][T]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BZ%5D%5BX%5D%5E2%7D%7B%5BR%5D%5BT%5D%5E2%7D)
where,
= equilibrium constant = 16
[Z] = concentration of Z at equilibrium = 2.0 M
[R] = concentration of R at equilibrium = 2.0 M
[X] = concentration of X at equilibrium = 2.0 M
[T] = concentration of T at equilibrium = ?
Now put all the given values in the above expression, we get:
![16=\frac{(2.0)\times (2.0)^2}{(2.0)\times [T]^2}](https://tex.z-dn.net/?f=16%3D%5Cfrac%7B%282.0%29%5Ctimes%20%282.0%29%5E2%7D%7B%282.0%29%5Ctimes%20%5BT%5D%5E2%7D)
![[T]=0.5M](https://tex.z-dn.net/?f=%5BT%5D%3D0.5M)
Therefore, the equilibrium concentration of T(g) is 0.5 M
So basically you, then, finally, you