The electric output of the plant is 48.19 MW
First we need to calculate the water power, it is given by the formula
WP=ρQgh
Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head
Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW
Now the overall efficiency of the hydroelectric power plant is given as
η=
Plugging the values in the above equation
0.84=EP/57.38
EP=48.19 MW
Therefore, the electric output of the plant is 48.19 MW.
Answer:
6,600N
Explanation:
According to second law of motion, Force = mass × acceleration
If acceleration = change in velocity/time = 15/0.10
Acceleration = 150m/s²
Given mass = 44kg
Force = 44× 150
Force = 6,600N
Magnitude of the average force exerted on the passenger during this time is 6,600N
I can't make sense of this question. Julie's throwing the ball, so it's leaving her rather than arriving at her ???