Question 8 (5 points)

Chemistry

1 answer:

Fynjy0 [20]2 years ago

8 0

[H+][OH-]=10-¹⁴

We are using this formula because we need to find the H+

substitute the value given for hydronium ion for OH-

[H+][4.19×10⁵]=10-¹⁴

[H+]=10-¹⁴÷4.19×10⁵

[H+]=2.387×10-¹⁹

Then the pH of the solution will be

pH= –log¹⁰ [H+]

pH = –log¹⁰ [2.387×10-¹⁹]

pH= –log¹⁰2.387+19log¹⁰

= –0.378+19

pH =18.622

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If 17. 6 g of hcl are used to produce a 14. 5 l solution, what is the ph of the solution?.

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This problem is providing us with the mass of hydrochloric acid and the volume of solution and asks for the pH of the resulting solution, which turns out to be 1.477.

<h3>pH calculations</h3>

In chemistry, one can calculate the pH of a solution by firstly obtaining its molarity as the division of the moles of solute by the liters of solution, so in this case for HCl we have:

$M=\frac{17.6g*\frac{1mol}{36.46g} }{14.5L} \\\\M=0.0333 M$

Next, due to the fact that hydrochloric acid is a strong acid, we realize its concentration is nearly the same to the released hydrogen ions to the solution upon ionization. Thereby, the resulting pH is:

$pH=-log(0.0333)\\\\pH=1.477$