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just olya [345]
2 years ago
13

Question 8 (5 points)

Chemistry
1 answer:
Fynjy0 [20]2 years ago
8 0

[H+][OH-]=10-¹⁴

We are using this formula because we need to find the H+

substitute the value given for hydronium ion for OH-

[H+][4.19×10⁵]=10-¹⁴

[H+]=10-¹⁴÷4.19×10⁵

[H+]=2.387×10-¹⁹

Then the pH of the solution will be

pH= –log¹⁰ [H+]

pH = –log¹⁰ [2.387×10-¹⁹]

pH= –log¹⁰2.387+19log¹⁰

= –0.378+19

pH =18.622

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A student preforms a chemical reaction in which 35 grams of hydrogen and 65 grams of oxygen reacted to form water. What is the m
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Answer:

Mass of water = 73.08 g

Explanation:

Given data:

Mass of hydrogen = 35 g

Mass of oxygen = 65 g

Mass of water = ?

Solution:

First of all we will write the balanced chemical equation:

2H₂  + O₂   →    2H₂O

Number of moles of hydrogen = mass/ molar mass

Number of moles of hydrogen =  35 g/ 2 g/mol

Number of moles of hydrogen = 17.5 mol

Number of moles of oxygen = 65 g / 32 g/mol

Number of moles of oxygen = 2.03 moles

Now we compare the moles of water with moles hydrogen and oxygen.

                                     H₂               :              H₂O

                                      2                :                2

                                    17.5              :              17.5

                                       O₂             :            H₂O

                                      1                :               2

                                      2.03         :             2× 2.03 =4.06 mol

Number of moles of water produced by oxygen are less so oxygen is limitting reactant.

Mass of water:

           Mass of water = number of moles × molar mass

          Mass of water = 4.06 mol × 18 g/mol

           Mass of water = 73.08 g

8 0
4 years ago
Position always is relative to another object or location <br> options: True False
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Answer:

True

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A laboratory experiment requires 4.8 l of a 2.5 m solution of sulfuric acid (h2so4), but the only available h2so4 is a 6.0 m sto
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To determine the amount of 6.0 M H2SO4 needed for the preparation, equate the number of moles of the 6.0 M and 2.5 M H2SO4 solution. This is done as follows
 
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Substituting the known variables,
 
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5 0
3 years ago
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