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4 years ago

How does the roots of most plants obtain food for suvival

Chemistry

1 answer:

Lilit [14]4 years ago

3 0

Answer:

Cell Wall

Explanation:

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Dichlorine monoxide, Cl2O is sometimes used as a powerful chlorinating agent in research. It can be produced by passing chlorine

Amiraneli [1.4K]

Answer:

% yield = 82.5%

Explanation:

HgO + 2Cl₂ → HgCl₂ + Cl₂O

Our reactants are:

HgO and Cl₂

Our products are:

HgCl₂ + Cl₂O

We do not have information about moles of reactants, but we do know the theoretical yield and the grams of product, in this case Cl₂O, we have produced.

Percent yield = (Yield produced / Theoretical yield) . 100

Theoretical yield is the mass of product which is produced by sufficent reactant. We replace data:

% yield = (0.71 g/0.86g) . 100 = 82.5%

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3 years ago

Which particle of the atom has a negative charge?

Alex_Xolod [135]

C.) Electron has a negative charge.....

6 0

3 years ago

The enzyme, carbonic anhydrase, is a large zinc-containing protein with a molar mass of 3.00 x10^4 g/mol. Zn is 0.218% by mass o

tia_tia [17]

The mathematical expression for mass percent is given by:

$Mass percent = \frac{mass of the compound}{molar mass of the compound}\times 100$

Put the values,

$0.218 percent of zinc = \frac{mass of zinc}{3.00 \times 10^{4} g/mol}\times 100$

mass of zinc = $0.218 \times (3\times 100) g$

= $0.654 \times 100 g$ or 65.4 g

Now, number of moles of zinc = $\frac{given mass in g}{molar mass of zinc}$

= $\frac{65.4 g}{65.38 g/mol}$

= 1.00 mole

Number of atoms of zinc is calculated by the Avogadro number.

Now, according to mole concept

$6.022\times 10^{23}$ molecules of enzyme consists of $6.022\times 10^{23}$ atoms of zinc

So, 1 molecule of enzyme contains = $\frac{6.022\times 10^{23}atoms of zinc}{6.022\times 10^{23} }$

= 1 atom of zinc.

Hence, every carbonic anhydrase molecule consists of 1 atom of zinc.

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3 years ago

Is warm water or cold water more dense

diamong [38]

Cold water is denser

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3 years ago

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( urgent help needed!! 50pts + brainliest )

Ivanshal [37]

Answer:

Thorium-234 option a .......

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3 years ago

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