Ask question

Ask question

All categories

2 years ago

6

The rabbit habitat in this graph has enough water to support 94 rabbits, shelter will support 85 rabbits, and there is enough fo

od for 66 rabbits.

1 answer:

Alexus [3.1K]2 years ago

4 0

Answer:

85 rabbits is the carrying capacity

Explanation:

I believe it is 85 rabbita because the shelter ITSELF is able to carry/support 85 rabbits.

You might be interested in

14. Why does a sea breeze blow from the ocean toward the shore?

shepuryov [24]

A. The breeze blow from higher pressure over the water to the lower

4 0

3 years ago

What experimental evidence was provided for the nuclear model of an atom

UkoKoshka [18]

Alpha particles bouncing off of gold foil.

6 0

3 years ago

An ostrich runs north in a straight line for 21 meters. She then turns around and runs 25 meters back toward her nest (south) on

drek231 [11]

The ostrich runs 21 N then goes back by 25 S

The displacement is -4 S

21 - 25 = -4

6 0

3 years ago

I need help with this

Lelechka [254]

Answer:

The answer is its equal to the volume of its container.

--------------------------------------------------------------------------------

I hope this helps! :)

7 0

3 years ago

For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80

Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

$A\rightleftharpoons B$

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

$K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%} =0.25$

Thus, by recalling the Van't Hoff's equation, we can write:

$ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )$

Hence, we solve for the enthalpy change as follows:

$\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }$

Finally, we plug in the numbers to obtain:

$\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}$

Learn more:

5 0

3 years ago