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Sever21 [200]
2 years ago
11

What numbers are shown in the symbol for a radioactive nuclide

Chemistry
2 answers:
Bingel [31]2 years ago
6 0
The atomic # and the mass #. 
Iteru [2.4K]2 years ago
5 0

Answer:

The mass and atomic number

Explanation:

There are two numbers that are written in front of the symbol. The mass number (written above) and the atomic number (written below). In mass number is equal to the sum of protons and neutrons, the atomic number is equal to the number of protons in the nucleus. The unstable nuclei are due to excess of protons or neutrons. Radioactive atoms tend to emit them intermittently and randomly.

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Who described atoms as small spheres that could not be divided into anything smaller?
gtnhenbr [62]
John Dalton


"matter cannot be created nor destroyed or divided into smaller particles"
5 0
3 years ago
A gas has a volume of 5.0 L at a pressure of 50 KPa. What happens to the volume when the pressure is increased to 125?
Alexeev081 [22]
The volume becomes two. You have to use the equation P1 x V1 = P2 x V2 
P is pressure and V is volume.
P1 = 50     P2 = 125
V1 = 5       V2 = v (we don't know what it is)
Then set up the equation:
50 times 5 = 125 times v
250 = 125v
the divide both sides by 125 and isolate v
2 = v
Therefore the volume is decreased to 2.
Also, Boyle's Law explains this too: Volume and pressure are inversely related, This means that when one goes up the other goes down (ie when pressure increases volume decreases and vice versa). Becuase the pressure went up from 50 KPa tp 125 KPa the volume had to decrease.

7 0
3 years ago
An atom with an atomic number of 18 will have how many electrons in its innermost orbit
Paraphin [41]

Answer:

2 electrons

Explanation:

The K shell is the innermost orbit and it contains 2 electrons

6 0
3 years ago
Which term defines the distance from the focal point to either a lens or a mirror
nikklg [1K]
The focal length, like you said it's the distance between the FOCAL point and the mirror.


Hope this helps.... :)
3 0
3 years ago
the standard change in Gibbs free energy is Δ????°′=7.53 kJ/molΔG°′=7.53 kJ/mol . Calculate Δ????ΔG for this reaction at 298 K29
Vera_Pavlovna [14]

Answer:

ΔG = 16.218 KJ/mol

Explanation:

  • dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
  • ΔG = ΔG° - RT Ln Q

∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol

∴  R = 8.314 J/K.mol

∴ T = 298 K

∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]

⇒ Q = 0.00300 / 0.100 = 0.03

⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))

⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )

5 0
3 years ago
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