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OverLord2011 [107]
3 years ago
8

2nd Semester Unit 1 Extra Credit!!! Can someone help me please?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
3 0
O goes over 22, N goes over -95, an I goes over 24, T goes over 16, V goes over -796, and those are the ones im sure of
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NEED ANSWER ASAP<br> MARKING BRAINLIEST
ra1l [238]

Answer:

p \: is \: unknown \: number \: of \: players \: that \: left \\ 55 -p  = 48

8 0
3 years ago
22 gallons of gas cost $65.56 what is the unit rate for one gallon of gas
Kitty [74]
Hey there!

If we would want to find out what it would be, we would have to divide it.

Your correct answer would be (2.98)

I did 65.56/22.

Hope this helps you!
7 0
3 years ago
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You invest $1300 in account that has an annual interest rate of 5% compounded annually. How much money will be in the account af
deff fn [24]
If you think about it and you use a calculator and do 1300×5% it will give you a number and divide it by 10 and there you should get you answer like that.
4 0
2 years ago
Find the value of x to the nearest degree <br>a. 30<br>b. 60<br>c. 70<br>d. 85
storchak [24]
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7 0
3 years ago
Could someone help me, please?
k0ka [10]

We can rewrite the expression under the radical as

\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4

then taking the fourth root, we get

\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|

Why the absolute value? It's for the same reason that

\sqrt{x^2}=|x|

since both (-x)^2 and x^2 return the same number x^2, and |x| captures both possibilities. From here, we have

\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|

The absolute values disappear on all but the b term because all of \dfrac32, a^2 and c^4 are positive, while b^3 could potentially be negative. So we end up with

\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4

3 0
3 years ago
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