Answer:
Explanation:During the nifty home experiment, a playing card was placed on top of a glass and then a quarter was placed on top of the card. When the card was pushed, the quarter fell into the glass. Why did the quarter fall into the glass? The quarter fell in the glass because of gravity.
Answer:
3-methylenehexane
Explanation:
In this case, we have <u>two clues</u>.
<u>1) The hydrogenation reaction</u>
<u>2) The ozonolysis reaction</u>
See figure 1.
With this in mind, lets analyze each clue. In the first reaction, we know that only 1 molecule of is added to the unknown molecule. This indicates that we only have <u>1 double bond</u> in the molecule. Now, the next question is <u>where is placed the double bond?</u>
To answer this question, we have to use the second clue. In the ozonolysis reaction, a double bond is broken and is replaced with a carbonyl group. If, <u>formaldehyde</u> is formed the double bond is formed with a <u>primary carbon</u>. The primary carbons in the structure (given in the first reaction: 3-methylhexane) are carbons 1, 6, and 7. So, the double bond can be placed between carbons:
a) 6 and 5
b) 7 and 3
c) 1 and 2
To decide which one is the position of the double bond we have to keep in mind the <u>second product</u> of the ozonolysis reaction a <u>ketone</u>. With this in mind, the carbon bonded to the <u>primary one</u> (deduced by the formaldehyde) it has to be a <u>tertiary carbon</u>. The only option that has a primary carbon bonded to tertiary carbon is <u>b)</u>. (See figure 2)
Finally, with this in mind the structure is <u>3-methylenehexane</u>. To be sure, we can <u>check the formula</u> for the compound, and the <u>reactions</u>. (See figure 3)
I hope it helps!
Answer:
Conduction is heat transfer through the direct contact of two subjects. The best example of this would be C, because it is the direct transfer of heat from the lightbulb to your hand. :)
Answer:
a. 52.8
Explanation:
To find the number of moles of HCl we use the relation M₁V₁=M₂V₂
where M₁ is the initial molarity, M₂ the new molarity, V₁ the initial volume used, and V₂ the final volume obtained.
M₁=7.91 M
M₂=2.13 M
V₁=?
V₂=196.1 mL
Replacing these values in the relationship.
M₁V₁=M₂V₂
7.91 M× V₁=2.13 M×196.1 mL
V₁=(2.13 M×196.1 mL)/7.91 M
=52.8 mL