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vesna_86 [32]
2 years ago
15

Newtons second law in words??​

Physics
1 answer:
Dennis_Churaev [7]2 years ago
5 0

Answer:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object

Explanation:

it's newton's second law

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A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area of 0.500 m2 .
vesna_86 [32]

Answer:

The energy of the wave is 1.435 x 10⁻⁴ J

Explanation:

Given;

area of the window, A = 0.5 m²

the rms value of the field, E = 0.06 V/m

The peak value of electric field is given by;

E_o = \sqrt{2} *E_{rms}\\\\E_o = \sqrt{2}*0.06\\\\E_o = 0.0849 \ V/m

The average intensity of the wave is given by;

I_{avg} = \frac{c \epsilon_o E_o^2 }{2}\\\\I_{avg} =  \frac{(3*10^8)( 8.85*10^{-12}) (0.0849)^2 }{2}\\\\I_{avg} = 9.569*10^{-6} \ W/m^2

The average power of the wave is given by;

P = I x A

P = (9.569 x 10⁻⁶ W/m²) (0.5 m²)

P = 4.784 x 10⁻⁶ W

The energy of the wave is given by;

E = P x t

E = (4.784 x 10⁻⁶ W)(30 s)

E = 1.435 x 10⁻⁴ J

Therefore, the energy of the wave is 1.435 x 10⁻⁴ J

3 0
2 years ago
A speed-time graph shows a car moving at 10 m/s for 10 s. The cars speed constantly decreases until it comes to a stop at 30 s.
Ray Of Light [21]

speed of the car at t = 10 s is given as 10 m/s

now at t = 30 s car comes to rest so v = 0

now in this velocity time graph we can say slope will show the acceleration of the car as we know that acceleration is rate of change in velocity

a = \frac{v_f - v_i}{\Delta t}

as we know that

v_f = 0

v_i = 10 m/s

\Delta t = (30 - 10) = 20 s

now from above formula

a = \frac{0 - 10}{20} = -0.5 m/s^2

So slope of the graph will represent the acceleration of car which is 0.5 m/s^2

5 0
3 years ago
Read 2 more answers
Which of these types of electromagnetic radiation has the lowest energy? _____
ValentinkaMS [17]
The answer would be radio waves
5 0
3 years ago
Read 2 more answers
Q.1 Lorna built the circuit diagram below. All the bulbs are identical. (a) Complete the table below by writing on or off for ea
irga5000 [103]

Answer:

on and off

Explanation:

if there are switches, it can change if the electricity can get to the bulb or not. if it appears that there is no pathway for the electricity to get to the light bulb, it is of, if there is a pathway, its on

8 0
2 years ago
What would Hubble's constant be if we found one galaxy moving away at 30,000 km/s at a distance of 600 Mpc?
lora16 [44]

Answer:

H₀ = 1.6 x 10⁻¹⁸ s⁻¹

Explanation:

The Hubble's Constant can be found by the following formula:

v = H_o D\\\\H_o = \frac{v}{D}

where,

H₀ = Hubble's Constant = ?

v = speed of galaxy = 30000 km/s = 3 x 10⁷ m/s

D = Distacance = 600 Mpc = (6 x 10⁸ pc)(3.086 x 10¹⁶ m/1 pc)

D = 18.52 x 10²⁴ m

Therefore,

H_o = \frac{3\ x\ 10^7\ m/s}{18.52\ x\ 10^{24}\ m}

<u>H₀ = 1.6 x 10⁻¹⁸ s⁻¹</u>

3 0
2 years ago
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