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anyanavicka [17]

3 years ago

8

The voltage across a resistor is found to be 1.5 V. It is also found that there is a charge of 2 Coulombs passing through the re

sistor within 10 seconds. What is the value of the resistor in ohms

1 answer:

djverab [1.8K]3 years ago

8 0

Answer:

R = 7.5 Ω

Explanation:

If the resistor is in the linear zone of operation, the resistance must obey Ohm's Law:

$V = I*R (1)$

By definition, the current flowing through the resistor, is equal to the charge passing through the resistor, per unit time.
So, we can write the following expression for the current I:

$I =\frac{\Delta Q}{\Delta t} = \frac{2C}{10s} = 0.2 A (2)$

From (1) and (2) we can solve for R, as follows:

$R =\frac{V}{I} = \frac{1.5V}{0.2A} = 7.5 \Omega$

The value of the resistor is 7.5 Ω.

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A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2. Compu

boyakko [2]

Answer:

0.42 m/s²

Explanation:

r = radius of the flywheel = 0.300 m

w₀ = initial angular speed = 0 rad/s

w = final angular speed = ?

θ = angular displacement = 60 deg = 1.05 rad

α = angular acceleration = 0.6 rad/s²

Using the equation

w² = w₀² + 2 α θ

w² = 0² + 2 (0.6) (1.05)

w = 1.12 rad/s

Tangential acceleration is given as

$a_{t}$ = r α = (0.300) (0.6) = 0.18 m/s²

Radial acceleration is given as

$a_{r}$ = r w² = (0.300) (1.12)² = 0.38 m/s²

Magnitude of resultant acceleration is given as

$a = \sqrt{a_{t}^{2} + a_{r}^{2}}$

$a = \sqrt{0.18^{2} + 0.38^{2}}$

$a$ = 0.42 m/s²

8 0

3 years ago

A slice of cheese has a mass of 40 g and a volume of 23 cm^3. What is the density of the cheese in units of g/cm^3 and g/mL?

Mila [183]

The mathematical and proportional relationship between mL and $cm ^ 3$ said us that $1cm ^ 3$ is equivalent to 1mL.

If the density is considered as the amount of mass per unit volume we will have to

$\rho = \frac{m}{V}$

here,

m = mass

V = Volume

Replacing we have that

$\rho = \frac{40g}{23cm^3}$

$\rho = 1.739g/cm^3$

As $1mL = 1cm^3$ we have that the density in g/mL is,

$\rho = 1.739g/mL$

6 0

3 years ago

Explain why a diverging lens is used to correct nearsightedness (difficulty seeing objects far away).

Darina [25.2K]

Answer:

so that it can diverge the light to make sure that it focused on the ratina and the image is formed.

Explanation:

nearsightedness is when the light is focused in front of the ratina and for an image to be formed in the eye, the light must be focused on the ratina so to correct that we use the diverging lenses so that it will diverge the light and allow the cornea and the lens to converge it so it is focused on the ratina.

8 0

3 years ago

Read 2 more answers

What is the total entropy change if a 0.280 efficiency engine takes 3.78E3 J of heat from a 3.50E2 degC reservoir and exhausts i

babymother [125]

Answer:

$\Delta S=1.69J/K$

Explanation:

We know,

$\eta=1-\frac{T_2}{T_1}=1-\frac{Q_2}{Q_1}$ ..............(1)

where,

η = Efficiency of the engine

T₁ = Initial Temperature

T₂ = Final Temperature

Q₁ = Heat available initially

Q₂ = Heat after reaching the temperature T₂

Given:

η =0.280

T₁ = 3.50×10² °C = 350°C = 350+273 = 623K

Q₁ = 3.78 × 10³ J

Substituting the values in the equation (1) we get

$0.28=1-\frac{Q_2}{3.78\times 10^{3}}$

or

$\frac{Q_2}{3.78\times 10^3}=0.72$

or

$Q_2=3.78\times 10^3\times0.72$

⇒ $Q_2 =2.721\times 10^3 J$

Now,

The entropy change ( $\Delta S$ ) is given as:

$\Delta S=\frac{\Delta Q}{T_1}$

or

$\Delta S=\frac{Q_1-Q_2}{T_1}$

substituting the values in the above equation we get

$\Delta S=\frac{3.78\times 10^{3}-2.721\times 10^3 J}{623K}$

$\Delta S=1.69J/K$

7 0

3 years ago

Can somebody help me please

Eddi Din [679]

51 inches.

This is because a stem-plot is formatted as so:

If it’s 5 on the left side of the line, anything on the right is the ones place making possible numbers 51, 53, 56, etc.

Hope this helps!

3 0

3 years ago