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Oksanka [162]
3 years ago
15

Choose the correct answer

Physics
1 answer:
irina1246 [14]3 years ago
6 0

Answer:

The average velocity has magnitude = 10 km/h , direction: east

Explanation:

In order to find the average velocity of the car we need to know the final and initial positions, and the time that took to get from one to the other.

Notice that since its movement was 60 km straight east and then from there 40 km straight west, the car is positioned at 20 km to the east of its initial departure point. therefore the vector change in position is a vector 20 km in magnitude, and direction towards the east.

Since it took the car a total of 1.33 hours plus 0.67 hours to reach its final position, the total time elapsed is: 1.33 + 0.67 hours = 2 hours.

Then,the velocity vector has magnitude; 20 km / 2 hours = 10 km/hour

As we mentioned above. the direction of the velocity vector is east.

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Two identical point charges are 3.00 cm apart. find the charge on each of them if the force or repulsion is 4.00 x 10^-7. (Use C
DanielleElmas [232]

Answer:

Charge on each is 2 x 10⁻¹⁰.

Explanation:

We know that Force between two point charges is given b the Coulomb's law as:

F = kq₁q₂/r^2

k = 9 x 10^9

r = 3.00 cm

= 0.03 m

q₁ = q₂

F = 4.00 x 10^-7

Rearranging the formula, we get:

F = k q²/r²

q² = Fr²/k

q² = 4 x 10⁻⁷ x 0.03²/(9x10⁹)

q² = 4 x 10⁻²⁰

q = 2 x 10⁻¹⁰

As there is force of repulsion between the charges, the charges must be both positive or both negative.

3 0
3 years ago
A box weighing 43.2 N is pulled horizontally until it slides uniformly lat a constant
GREYUIT [131]

Your diagram should include four forces:

• the box's weight, pointing down (magnitude <em>w</em> = 43.2 N)

• the normal force, pointing up (mag. <em>n</em>)

• the applied force, pointing the direction in which the box is sliding (mag. <em>p</em> = 6.30 N, with <em>p</em> for "pull")

• the frictional force, pointing oppoiste the applied force (mag. <em>f</em> )

The box is moving at a constant speed, so it is inequilibrium and the net forces in both the vertical and horizontal directions sum to 0. By Newton's second law, we have

<em>n</em> + (-<em>w</em>) = 0

and

<em>p</em> + (-<em>f</em> ) = 0

So then the forces have magnitudes

<em>w</em> = 43.2 N

<em>n</em> = <em>w</em> = 43.2 N

<em>p</em> = 6.30 N

<em>f</em> = <em>p</em> = 6.30 N

5 0
3 years ago
If a car traveling at 60 km/h will skid 20m when its brakes lock, how far will it skid if it's traveling at 120 km/h when it's b
pantera1 [17]
<span>If a mouse and an elephant both run with the same kinetic energy, can you say ... 3. if a car traveling at60 km/h will skid 20 m when its brakes lock, how far will it skid if it is traveling at 120 km/h when its brakes lock? (This question is typical on ...</span><span>just get this and figure it out and this is your answer </span>
7 0
3 years ago
Calculate the volume of this regular solid. A cylinder labeled B at the top, 13 centimeters high with a radius of 4 centimeters.
Kryger [21]

Answer:

The volume of the cylinder is 653.71\ \text{cm}^3

Explanation:

Given that,

The height of the cylinder is 13 cm

Radius of the cylinder is 4 cm

We need to find the volume of the cylinder. The formula that is used to find the volume of a cylinder is given by :

V=\pi r^2 h\\\\V=\dfrac{22}{7} \times (4)^2 \times 13\\\\V=653.71\ \text{cm}^3

So, the volume of the cylinder is 653.71\ \text{cm}^3

4 0
3 years ago
Read 2 more answers
The density of a solid cube is 678.2 kg/m^3. (Note that each edge is 4.8 cm in length and the mass is 75g.) When the cube is pla
Galina-37 [17]

Answer:

Part a)

F = 0.735 N

Part b)

percentage = 67.9%

Explanation:

As we know that mass of the cube is given as

M = \rho V

M = \rho a^3

M = (678.2) (4.8 \times 10^{-2})^3

M = 0.075 kg

Now we know that cube is floating in the water

So net force due to weight of the cube must be counter balanced by buoyancy force on the liquid

so we have

F_b = mg

F_b = 0.075 \times 9.81

F_b = 0.735 N

Part b)

Percentage of volume submerged into the liquid is given as

F_b = \rho V g

0.735 = 1000 V \times 9.8

V = 7.71 \times 10^{-5} m^3

now percentage of submerged liquid is given as

percentage = \frac{7.71 \times 10^{-5}}{(4.8 \times 10^{-2})^3}\times 100

percentage = 67.9%

5 0
3 years ago
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