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gregori [183]
3 years ago
14

Two solenoids are nested coaxially such that their magnetic fields point in opposite directions. Treat the solenoids as ideal. T

he outer one has a radius of 20 mm, and the radius of the inner solenoid is 10 mm. The length, number of turns, and current of the outer solenoid are, respectively, 21.5 cm, 539 turns, and 5.33 A. For the inner solenoid the corresponding quantities are 18.1 cm, 395 turns, and 1.95 A. At what speed, v1, should a proton be traveling, inside the apparatus and perpendicular to the magnetic field, if it is to orbit the axis of the solenoids at a radius of 5.95 mm?
Physics
1 answer:
ch4aika [34]3 years ago
5 0

Answer:

6700 m/s

Explanation:

The magnetic field due to a solenoid is given by B = μ₀in where i = current, n = number of turns per unit length = N/l and μ₀ = 4π × 10⁻⁷ H/m

Let B₁ be the magnetic field for the outer solenoid. For this solenoid, i = 5.33 A, n = N/l = 539 turns/0.215 m since l = 21.5 cm = 0.215 m

B₁ = 5.33 A × 539 turns/0.215 m × 4π × 10⁻⁷ H/m = 0.017 T

Let B₂ be the magnetic field for the inner solenoid. For this solenoid, i = 1.95 A, n = N/l = 395 turns/0.181 m since l = 18.1 cm = 0.181 m

B₂ = 1.95 A × 395 turns/0.181 m × 4π × 10⁻⁷ H/m = 0.0053 T

Since the magnetic fields are in opposite direction, the net magnetic field is B = B₁ - B₂ = 0.017 T - 0.0053 T = 0.0117 T.

This magnetic field produces a magnetic force on the proton which is equal to the centripetal force on the proton. So at r = 5.95 mm

Bev = mv²/r

v = Ber/m = 0.0117 T × 1.6 × 10 ⁻¹⁹ C × 5.95 × 10⁻³ m/1.67 10⁻²⁷ kg = 6669.7 m/s ≅ 6700 m/s

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PtichkaEL [24]

Answer:

<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>

Explanation:

Force, F:

{ \bf{F=BeV}}

F is magnetic force.

B is the magnetic flux density.

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{ \sf{20 = (5 \times e \times 4)}} \\ { \sf{20e = 20}} \\ { \sf{e = 1 \: coulomb}}

8 0
3 years ago
A rectangular field is 300 meters long and 300 meters wide. What is the area of the field in square kilometers? Do not round you
dexar [7]

Answer:

Area of the rectangular field in kilometers is 0.09 km^2

Explanation:

We know that 1 kilometers = 1000 meters

                    since we need to find the area in unit of kilometers

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The power supply for your answering machine is a small black cube that plugs directly into an electric outlet. The main componen
svet-max [94.6K]

If the transformer’s primary coil has 20 times as many turns of wire in it as the secondary coil has, then the secondary coil provides a small voltage rise for the large amount of current that flows through it.

Answer: Option B

<u>Explanation:</u>

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Without a long separation over which to do chip away at the charges streaming in the loop, the transformer delivers just a little ascent in the voltage of those charges. Be that as it may, the coil can give this little voltage to ascend to a huge current without requiring an excess of power supply from the input circuit.

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3 years ago
A 3.0 m tall, 40 cm diameter concrete column supports a 235,000 kg load. by how much is the column compressed? assume young's mo
statuscvo [17]
The Young modulus E is given by:
E= \frac{F L_0}{A \Delta L}
where 
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A is the cross-sectional area perpendicular to the force applied
L_0 is the initial length of the object
\Delta L is the increase (or decrease) in length of the object.

In our problem, L_0 = 3.0 m is the initial length of the column, E=3.0 \cdot 10^{10}N/m^2 is the Young modulus. We can find the cross-sectional area by using the diameter of the column. In fact, its radius is:
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So, the column compresses by 1.83 millimeters.
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