What is the formule for calcium nitrate trihydrate

An object that is farther from a converging lens than its focal point always has an image that is _____.

bearhunter [10]

Smaller in size (Pt. Sized)

5 0

3 years ago

The illustration shows the basic unit of life it is

vlabodo [156]

The answer is A, Cell. This is the basic structure of a cell.

6 0

3 years ago

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Oil explorers set off explosives to make loud sounds, then listen for the echoes from underground oil deposits. Geologists suspe

Elenna [48]

Answer:

dg= 942m

Explanation:

given the depth of the granite Us dg = 500m

time between the explosion t = 0.99s

the speed of sound in granite is Vg = 6000m/s

First of all calculate the time it takes the sound waves to travel down through the lake

Vw = dw/t1

t1 = dw/Vw

t1 = 500/1480

t1 = 0.338s.

Let dg be the depth of the granite basin, so the time it takes for the sound to travel down through the granite is t2 = dg/6000m/s......equation(1)

So the total time it takes to travel down to the oil surface will be

t1/2 = t1 + t2

t1/2= 0.338 + dg/6000.

since the reflection on the oil does not change the speed of sound, the sound will take travelling upto the surface the same time it takes to reach the oil

so; t = 2 t1/2

t1/2 = t/2 = 0.99s/2 = 0.495

Now insert into the values of t1/2 into the equation (1) and solve for dg;

we get 0.495 = 0.338 + dg/6000

dg = (0.495 - 0.338) x 6000

dg = 942m.

3 0

3 years ago

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A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic fie

Olin [163]

Answer:

The maximum torque is $\tau_{max} = 1.139 *10^{-7} \ N \cdot m$

Explanation:

From the question we are told that

The length of the wire is $l = 26.0 \ cm = 0.26 \ m$

The current flowing through the wire is $I = 5.77mA = 5.77 *10^{-3} \ A$

The magnetic field is $B = 3.67 \ mT = 3.67 *10^{-3 } T$

The maximum torque is mathematically evaluated as

$\tau_{max} = \mu B$

Where $\mu$ is the magnetic dipole moment which is mathematically represented as

$\mu = \frac{I l^2}{4 \pi n }$

Where $n$ is the number of turns which from the question is 1

substituting values

$\mu = \frac{ 5.77 *10^{-3} * 0.26^2}{4 * 3.142* 1 }$

$\mu = 3.10 4* 10^{-5} A m^2$

Now

$\tau_{max} = 3.104 *10^{-5} * 3.67 *10^{-3}$

$\tau_{max} = 1.139 *10^{-7} \ N \cdot m$

7 0

3 years ago

An object is located 50 cm from a converging lens having a focal length of 15 cm. Which of the following is true regarding the i

Diano4ka-milaya [45]

Answer:

It is real, inverted, and smaller than the object.

Explanation:

First of all, we can use the lens equation to find the location of the image:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}$

where

q is the distance of the image from the lens

f = 15 cm is the focal length (positive for a converging lens)

p = 50 cm is the distance of the object from the lens

Solving the equation for q,

$\frac{1}{q}=\frac{1}{15 cm}-\frac{1}{50 cm}=0.047 cm^{-1}\\q=\frac{1}{0.047 cm^{-1}}=21.3 cm$

The distance of the image from the lens is positive, so we can already conclude that the image is real.

Now we can also write the magnification equation:

${h_i}=-h_o \frac{q}{p}$

where $h_i, h_o$ are the size of the image and of the object, respectively.

Substituting p = 50 cm and q = 21.3 cm, we have

${h_i}=-h_o \frac{21.3 cm}{50 cm}=-0.43 h_o$

So from this relationship we observe that:

$|h_i| < |h_o|$ --> this means that the image is smaller than the object, and

$h_i < 0$ --> this means that the image is inverted

so, the correct answer is

It is real, inverted, and smaller than the object.

4 0

3 years ago