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3 years ago

A lab analysis of 0.502 g of Scandium (Sc) reaction with Oxygen (O2) from Air resulted

Chemistry

1 answer:

VARVARA [1.3K]3 years ago

3 0

The empirical formula of the metal oxide would be $Sc_2O_3$

<h3>What is empirical formula?</h3>

Mass of scandium = 0.502g

Mass of scandium + oxygen = 0.768g

Mass of oxygen = 0.768 - 0.502 = 0.266g

Mole of scandium = 0.502/44.95 = 0.011

Mole of oxygen = 0.266/16 = 0.017

Divide by the lowest:

Scandium = 0.011/0.011 = 1

Oxygen = 0.017.0.011 = 1.5

Thus, the empirical formula of the compound would be $ScO_1.5$ or $Sc_2O_3$

More on empirical formula can be found here:brainly.com/question/14044066

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If 1.20 moles of an ideal gas occupy a volume of 18.2 l at a pressure of 1.80 atm, what is the temperature of the gas, in degree

scoundrel [369]

We can calculate for temperature by assuming the equation for ideal gas law:

P V = n R T

Where,

P = pressure = 1.80 atm

V = volume = 18.2 L

n = number of moles = 1.20 moles

R = gas constant = 0.08205746 L atm / mol K

Substituting to the given equation:

T = P V / n R

T = (1.8 atm * 18.2 L) / (1.2 moles * 0.08205746 L atm / mol K)

T = 332.70 K

We can convert K unit to ˚C unit by subtracting 273.15 to Kelvin, therefore

T = 59.55 ˚C

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4 years ago

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Kitty [74]

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4 years ago

Cryolite (Na3AlF6) is used in the production of aluminum from its ores. It is made by the reaction 6 NaOH 1 Al2O3 1 12 HF 8n 2 N

kap26 [50]

Answer: The mass of cryolite produced in the reaction is 1181.8 g

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of aluminium oxide = 287 g

Molar mass of aluminium oxide = 102 g/mol

Putting values in equation 1, we get:

$\text{Moles of aluminium oxide}=\frac{287g}{102g/mol}=2.814mol$

The given chemical reaction follows:

$6NaOH+Al_2O_3+12HF\rightarrow 2Na_3AlF_6+9H_2O$

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 2.814 moles of aluminium oxide will produce = $\frac{2}{1}\times 2.814=5.628mol$ of cryolite

Now, calculating the mass of cryolite by using equation 1:

Moles of cryolite = 5.628 moles

Molar mass of cryolite = 210 g/mol

Putting values in equation 1, we get:

$5.628mol=\frac{\text{Mass of cryolite}}{210g/mol}\\\\\text{Mass of cryolite}=(5.628mol\times 210g/mol)=1181.8g$

Hence, the mass of cryolite produced in the reaction is 1181.8 g

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3 years ago

1. How much magnesium oxide is produced if 12.1 g of magnesium reacts with 16 g of oxygen

melamori03 [73]

Answer:

20.2g (3 s.f.)

Explanation:

Please see attached picture for full solution.

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3 years ago

Identify the reactants in the following chemical reaction: . 6H2O + 6CO2 ---> C6H12O6 + 6O2. . a. 6CO2 +C6H12O6. b. 6H20 + 60

Nikolay [14]

The correct answer is d. 6H20 + 6CO2.

The reactant in the chemical reaction 6H2O + 6CO2 ---> C6H12O6 + 6O2 is 6H20 + 6CO2. Remember that the reactant is always at the left side of the equation. So the correct answer is 6H20 + 6CO2 since it's in the left of the equation. I hope this answer helped you.

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3 years ago

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