1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yuliya22 [10]
2 years ago
6

What is pseudo - order reaction​

Chemistry
2 answers:
zubka84 [21]2 years ago
7 0

Explanation:

The reactions which are not truly of first order but become reactions of first order under certain conditions are called pseudo first order reactions.

For example, hydrolysis of ester

mojhsa [17]2 years ago
6 0

Explanation:

<em>The reactions which are not truly of first order but become reactions of first order under certain conditions are called pseudo first order reactions</em>.

You might be interested in
How much heat energy must be absorbed to completely melt 35.0 grams of H2O(s) at 0°C?
Cerrena [4.2K]
(35/18.02)(6.02kJ)=11.6926 kiloJoules
5 0
3 years ago
Which of the following has dispersion forces as its only intermolecular force? A) CH4 B) HCl C) C6H13NH2 D) NaCl E) CH3Cl
Natali5045456 [20]
D is the right answer
4 0
3 years ago
A blacksmith heated an iron bar to 1445 °C. The blacksmith then tempered the metal by dropping it into 42,800 mL of
Wittaler [7]

Answer:

6626 g

Explanation:

Given that:

Density of water = 1.00 g/ml, volume of water = 42800 ml.

Since density = mass/ volume

mass of water = volume of water * density of water = 42800 ml * 1 g/ml = 42800 g

Initial temperature of water = 22°C and final temperature of water = 45°C.

specific heat capacity for water = 4.184 J/g°C

ΔT water = 45 - 22 = 23°C

For iron:

mass = m,  

specific heat capacity for iron  = 0.444 J/g°C

Initial temperature of iron = 1445°C and final temperature of water = 45°C.

ΔT iron = 45 - 1445 = -1400°C

Quantity of heat (Q) to raised the temperature of a body is given as:

Q = mCΔT

The quantity of heat required to raise the temperature of water is equal to the temperature loss by the iron.

Q water (gain) + Q iron (loss) = 0

Q water = - Q iron

42800 g ×  4.184 J/g°C × 23°C = -m × 0.444 J/g°C × -1400°C

m = 4118729.6/621.6

m = 6626 g

8 0
3 years ago
A tank of gas is found to exert 8.6 atm at 38°C. What would be the required
Vesna [10]

Answer:

36.2 K

Explanation:

Step 1: Given data

  • Initial pressure of the gas (P₁): 8.6 atm
  • Initial temperature of the gas (T₁): 38°C
  • Final pressure of the gas (P₂): 1.0 atm (standard pressure)
  • Final temperature of the gas (T₂): ?

Step 2: Convert T₁ to Kelvin

We will use the following expression.

K = °C +273.15

K = 38 °C +273.15 = 311 K

Step 3: Calculate T₂

We will use Gay Lussac's law.

P₁/T₁ = P₂/T₂

T₂ = P₂ × T₁/P₁

T₂ = 1.0 atm × 311 K/8.6 atm = 36.2 K

6 0
3 years ago
What is the gravitational potential energy of a 5 kg object that is 150
marusya05 [52]

Explanation:

Gravitational potential energy

= mgh

= (5kg)(9.81N/kg)(150m)

= 7357.5J.

5 0
3 years ago
Read 2 more answers
Other questions:
  • Where do proteins get the energy to combine co2 and other compounds in the calvin cycle?
    13·1 answer
  • Definition: The phase of matter where particles at extremely high temperatures become ionized. Example: The state of matter of t
    12·1 answer
  • Do elements of the halogen family lose one electron to become halide ions
    8·1 answer
  • 2A1Cl3 + 3Na CO3→ Al2(CO3)3 + 6NaCl
    5·1 answer
  • How many oxygen molecules are present in 113.97 liters of oxygen gas at stp?
    5·1 answer
  • Which of the following changes depending on the strength of the gravity field it is in?
    13·2 answers
  • Need help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    14·1 answer
  • Is iodine a atom,a molecule,an ion or a formule unit?
    13·1 answer
  • 15.La voiture ................... devant cet hôtel .Single choice.
    6·1 answer
  • If 50. 75 g of a gas occupies 10. 0 l at stp, 129. 3 g of the gas will occupy ________ l at stp.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!