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Veseljchak [2.6K]
4 years ago
15

The following equation shows the correct molecules formed in the reaction, but the products are incorrect. CH4 +202=H20+ CO2 How

would you correct the products?
Chemistry
1 answer:
Hunter-Best [27]4 years ago
5 0
For the equation to balance out, you would need 2 H2O on the product. That will give a total of 1 Carbon, 4 Hydrogens and 4 Oxygens on each side.
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Which type of bond is present in hydrogen sulfide (H2S)? The table of electronegativities is given
LuckyWell [14K]

Bonds formed between atoms can be classified as ionic and covalent

Ionic bonds are formed between atoms that have a high difference in the electronegativity values.

In contrast, bonds formed between atoms that have a difference in electronegativity lower than the ionic counterparts are polar covalent bonds.  If the atoms have very similar electronegativities, they form non-polar covalent bonds.

In H2S, the S atom is bonded to 2 H atoms. The electronegativity of H = 2.2 and S= 2.56. Since the difference is not high the bond formed will be covalent (polar covalent).

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4 years ago
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3 years ago
F a shell can hold a maximum of 32 electrons, what is the value of n? 2 3 4 5
Arte-miy333 [17]

Answer: 4

Explanation:

Principle Quantum Numbers: This quantum number describes the size of the orbital. It is represented by n.

Azimuthal Quantum Number: This quantum number describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number: This quantum number describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of m_l will be -2, -1, 0, +1, +2.

Given : a f subshell, thus l = 3 , Thus the subshells present would be 3, 2, 1, 0 and thus n will have a value of 4.

Also electrons give are 32.

The formula for number of electrons is 2n^2.

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Thus principal quantum no will be n= 4.

8 0
3 years ago
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<span>A.to create a solution of anions
B. to create a solution of cations
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3 years ago
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Copper(ii) chloride reacts with sodium nitrate to produce copper(ii) nitrate and sodium chloride.
zlopas [31]

Answer:

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3 years ago
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