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1 year ago

The weak base ionization constant (Kb) for HCO3 is equal to:

1 answer:

8 0

Weak bases are alkaline solution that does not get completely dissociated. The dissociation constant will be the ratio of the concentration of the products to the reactants.

<h3>What is a weak base ionization constant?</h3>

The weak base ionization constant is the equilibrium constant that is given as the division of the products of the ionization to the concentration of the reactants.

The reaction for HCO₃ is given as:

HCO₃⁻ + OH⁻ ⇄ CO₃²⁻ + H₂O

The value of Ka for the given reaction will be:

Ka = [CO₃²⁻][H₂O] ÷ [HCO₃⁻ ][OH⁻]

Therefore, the Ka of the weak carbonic acid is given as the ratio of the concentration of the products to the reactants.

Learn more about the weak ionization constant here:

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Calculate gram formula mass of LiCl(s)

Nadya [2.5K]

Answer:

The answer is 42, 39 grams of LiCl

Explanation:

We calculate the weight of 1 mol of LiCl, from the atomic weights of each element obtained from the periodic table:

Weight 1 mol LiCl= Weight Li + Weight Cl =6,94 g+ 35, 45 g= 42, 39grams

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3 years ago

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3 years ago

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rusak2 [61]

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3 years ago

What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?

mars1129 [50]

The concentration of solution in M or mol/L can be calculated using the following formula:

$C=\frac{n}{V}$ .... (1)

Here, n is number of moles and V is volume of solution in L.

The molecular formula of potassium sulfate is $K_{2}SO_{4}$ thus, there are 2 moles of potassium in 1 mol of potassium sulfate.

1 mol of potassium will be there in 0.5 mol of potassium sulfate.

Mass of potassium is 4.15 g, molar mass is 39.1 g/mol.

Number of moles can be calculated as follows:

$n=\frac{m}{M}$

Here, m is mass and M is molar mass

Putting the values,

$n=\frac{(4.15 g}{(39.1 g/mol}=0.1061 mol$

Thus, number of moles of $K_{2}SO_{4}$ will be $0.1061\times 0.5=0.053 mol$ .

The volume of solution is 225 mL, converting this into L,

$1 mL=10^{-3}L$

Thus,

$225 mL=0.225 L$

Putting the values in equation (1),

$C=\frac{(0.053 mol}{0.225 L}=0.236 M$

Therefore, concentration of potassium sulfate solution is 0.236 M.

4 0

3 years ago

using the same balanced equation, what is the number of moles of carbon dioxide produced from 3.750 moles of propane?

kondor19780726 [428]

Answer:

11.25moles of CO2

Explanation:

First, let us generate a balanced equation for the reaction of propane to produce CO2. This reaction called Combustion. It is a reaction in which propane burns in air (O2) to produce CO2 and H20. The equation is given below:

C3H8 + 5O2 —> 3CO2 + 4H2O

From the equation,

1mole of C3H8 produced 3moles of CO2.

Therefore, 3.750 moles of C3H8 will produce = 3.750 x 3 = 11.25moles of CO2

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2 years ago