Ans: Calcium sulfate.
K2SO4 (aq) + Ca(NO3)2 (aq) ⇒ 2KNO3 (aq) + CaSO4 (s)
Answer:
In your case, you have 8 protons and 10 electrons. This means that the atom will carry a total 2 xx (1-) = 2- net charge. Therefore, you are dealing with an anion that carries a 2- net charge, i.e. it has two more electrons than it does protons.
Answer:
The average pressure in the container due to these 75 gas molecules is
Explanation:
Here Pressure in a container is given as
Here
- P is the pressure which is to be calculated
- ρ is the density of the gas which is to be calculated as below
Here
mass is to be calculated for 75 gas phase molecules as
Volume of container is 0.5 lts
So density is given as
- is the mean squared velocity which is given as
Here RMS is the Root Mean Square speed given as 605 m/s so
Substituting the values in the equation and solving
So the average pressure in the container due to these 75 gas molecules is
The mass of the acid produced is 0.252 g from the information in the question.
<h3>What is neutralization?</h3>
The term neutralization refers to the reaction between an acid and a base that yileds salt and water only.
The equation of this reaction is; 2HCl + CaCO3 ----->CaCl2 + CO2 + H2O
Number of moles of CaCO3 = 0.350 g/100 g = 0.0035 moles
Since 2 moles of acid reacts with 1 mole of CaCO3
x moles acid reacts with 0.0035 moles of CaCO3
x = 0.007 moles
Mass of acid = 0.007 moles * 36 g/mol = 0.252 g
Learn more about neutralization: brainly.com/question/15395418
Answer:
A) 0.20 cm³
B) 49.7 m²
C) 99.99%
D) 17.7 mg
Explanation:
A) The density of a material represents the mass that it occupies in a "piece" of volume. Thus, the density (d) is the mass (m) divided by the volume (v):
d =m/v
If the mass is 40.0 mg = 0.04 g, and the density is 0.20 g/cm³, the volume is:
0.20 = 0.04/v
v = 0.04/0.20
v = 0.20 cm³
B) The surface area (S) is the are that is presented in each gram of the material, so, it's the area (a) divided by the mass (m):
S = a/m
If the mass is 40.0 mg = 0.04 g, and the surface area is 1242 m²/g, so:
1242 = a/0.04
a = 49.7 m²
C) The percent of mercury removed is the mass removed divided by the initial mass, this multiplied by 100%. The mass removed is the initial mass (m0) less the final mass (m), so:
%removed = [(7.748 - 0.001)/7.748] *00%
%removed = 99.99%
D) The final mass of the spongy material is it mass (10 mg) plus the mass removed of the mercury (7.748 - 0.001 = 7.747 mg), so:
m = 10 + 7.747
m = 17.747 mg
m = 17.7 mg