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rodikova [14]
3 years ago
13

Based on its location on the periodic table, which element would be most likely to form a negative ion?

Chemistry
2 answers:
Pavlova-9 [17]3 years ago
7 0
<span>Fluorine ONLY form\s an ion with a -1 charge. The other three are metals, and metals for positively charged ions.</span>
Viefleur [7K]3 years ago
5 0

<u>Answer:</u> The element which is most likely to form negative ion is fluorine.

<u>Explanation:</u>

An ion is formed when a neutral atom looses or gains electrons.

  • When an atom looses electrons, it results in the formation of positive ion known as cation.
  • When an atom gains electrons, it results in the formation of negative ion known as anion.

For the given options:

  • <u>Option A:</u> Aluminium

Aluminium is the 13th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^1

This element will loose 3 electrons to attain stable electronic configuration and will form Al^{3+} ion

  • <u>Option B:</u> Copper

Copper is the 29th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^9

This element will loose 2 electrons to attain stable electronic configuration and will form Cu^{2+} ion

  • <u>Option C:</u> Sodium

Sodium is the 11th element of the periodic table having electronic configuration of 1s^22s^22p^63s^1

This element will loose 1 electron to attain stable electronic configuration and will form Na^{+} ion

  • <u>Option D:</u> Fluorine

Fluorine is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

This element will gain 1 electron to attain stable electronic configuration and will form F^{-} ion

Hence, the element which is most likely to form negative ion is fluorine.

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3 years ago
How many moles of nitrogen, N, are in 61.0 g of nitrous oxide, N2O?
Oksana_A [137]

Answer:

2.77 mol N

Explanation:

M(N2O) = 2*14 + 16 = 44 g/mol

61.0 g * 1 mol/44g = (61/44) mol N2O

                       N2O ---- 2N

                    1 mol         2 mol

            (61/44) mol        x mol

x = (61/44)*2/1 = 2.77 mol N

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3 years ago
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4 years ago
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If a 4L solution is 80% concentrated lime juice and 20% water, how much 30% concentrated lime juice must be added so that the co
miv72 [106K]

The volume of 30% concentrated lime juice that must be added to a 4L solution of 80% concentrated lime juice and 20% water is 6 L.

<h3>What are mixtures?</h3>

Mixtures are substances which are formed when two or more substances are physically combined together.

Mixtures are heterogenous in nature and the constituents can be easily separated.

The volume of 30% concentrated lime juice that must be added to a 4L solution of 80% concentrated lime juice and 20% water, so that the concentration of the resulting solution is 50% concentrated lime juice is determined as follows:

Let the volume of 30% lime juice required be x;

total volume of lime juice = 0.3x

For 80% lime juice, volume of lime juice = 0.8 * 4 = 3.2 L

New volume of lime juice = 4 + x

New amount of lime juice added = 3.2 + 0.3x

Also, new amount of lime juice = 0.5 * ( 4 + x)

3.2 + 0.3x = 0.5 * ( 4 + x)

0.2x = 1.2

x = 6 L

In conclusion, the volume to be added is obtained from the percent concentration.

Learn more about percent concentration at: brainly.com/question/19379932

#SPJ1

7 0
2 years ago
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