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vampirchik [111]
3 years ago
13

What is the gpe of a 200 kg hot air ballon 21,000 m above the ground?

Physics
1 answer:
stiv31 [10]3 years ago
8 0

gravitational Potential energy is given by

GPE = mgh

here we have

m = 200 kg

h = 21000 m

now we will have

GPE = 200(9.8)(21000)

GPE = 4.116 \times 10^7 J

so GPE of balloon will be 41160000 J above the given height from ground

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PLZ HELP!!! Detailed PLZ!
Korolek [52]

Answer:

Potential Energy = 294J, Kinetic Engergy = 48.02J

Explanation:

We have these formulas:

Potential Energy = mass * gravitational force * height (m) = 1 * 9.8 * 30 = 294(J)

Kinetic Energy = 1/2 * mass * velocity^2 = 1/2 * 1 * 9.8^2 = 48.02 (J)

As the rock falling at an acceleration of 9.8m/s^2 which means for each second, the rock increases 9.8m/s. I think we are missing time to find the instantaneous velocity, the formula is (initial displacement - final displacement)/ (initial time - final time) which will directly give the final answer for you.

 

5 0
3 years ago
When a ball rolls down a hill, what energy conversion occurs?
Ludmilka [50]

Answer:

C

Explanation:

When a ball rolls down a hill, Potential Energy Conversion takes place to Kinetic Energy.

8 0
3 years ago
A 85.0 cm wire of mass 9.40 g is tied at both ends and adjusted to a tension of 39.0 N . When it is vibrating in its second over
kodGreya [7K]

Answer:

frequency = 104.80 Hz

wavelength = 0.567 m

frequency = 104.80 Hz

wavelength = 3.27 m

Explanation:

given data

mass m = 9.4 g = 9.4 ×10^{-3} m

length L = 85 cm = 0.85 m

tension  T = 39 N

to find out

frequency and wavelength

solution

first we find frequency for second overtone

f = 3 /2L × √(T/μ)   .............1

put here all value and

here μ = m/L = 9.4 ×10^{-3} / 0.85 = 1.10588 ×10^{-2} kg/m

f = 3 /2(0.85) × √(39/1.10588 ×10^{-2})

f = 104.80 Hz

and

wavelength is 2L/3

wavelength = 2(0.85) / 3

wavelength = 0.567 m

and

frequency = 104.80 Hz

and

wavelength by speed of sound i.e 343 m/s

wavelength = speed / f

wavelength = 343 / 104.80

wavelength = 3.27 m

3 0
3 years ago
Can someone please explain the last question?​
gregori [183]

Answer:

1666.67

Explanation:

1/2 x K x e^2.

1/2 x 1666.67 x 0.276^2

63.48 J

4 0
2 years ago
A rocket accelerates at a rate of 16.4m/s^2 for a distance of 50m. What is the speed at the
NARA [144]

Answer:

40.5 m/s

Explanation:

Given:

v₀ = 0 m/s

a = 16.4 m/s²

Δx = 50 m

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (16.4 m/s²) (50 m)

v = 40.5 m/s

4 0
3 years ago
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