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vampirchik [111]
3 years ago
13

What is the gpe of a 200 kg hot air ballon 21,000 m above the ground?

Physics
1 answer:
stiv31 [10]3 years ago
8 0

gravitational Potential energy is given by

GPE = mgh

here we have

m = 200 kg

h = 21000 m

now we will have

GPE = 200(9.8)(21000)

GPE = 4.116 \times 10^7 J

so GPE of balloon will be 41160000 J above the given height from ground

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3 years ago
A 0.23-f capacitor is desired. What area must the plates have if they are to be separated by a 3.8-mm air gap?
tia_tia [17]

The area of the plates must have is(A)= 9.91×10⁷ m²

<h3 /><h3>How can we calculate the value of a area of a capacitor?</h3>

To calculate the the value of a area of the plates of a capacitor, we are using the formula,

C=\frac{\epsilon_0 A}{d}

Or, A= \frac{C\times d}{\epsilon_0}

Here we are given,

C= The desired capacitance of a capacitor.

= 0.23F

d=distance of separation between the plates.

=3.8mm= 0.0038m.

\epsilon_0= permittivity of the vacuum.  

=8.854×10⁻¹²F/m

We have to calculate the area of the plates must have = A m².

Now we put the known values in the above equation, we can get

A= \frac{C\times d}{\epsilon_0}

Or, A=\frac{0.23\times 0.0038}{8.854\times 10^{-12}}

Or, A= 9.91×10⁷ m²

From the above calculation, we can conclude that the area of the plates must have is(A)= 9.91×10⁷m²

Learn more about Capacitor:

brainly.com/question/13578522

#SPJ4

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