It will land in your lap because there's different frames of motion relative to yourself. For example, if you're running at a speed of 6 mph, it doesn't mean you'll run as fast as the Earth spins. Also, since you're on the interior of the plane, any kind of wind or weather on the outside will not affect the coin. A law to back up this claim is Einsteins Special Law of Relativity.
Answer:
the speed of the block when it reaches point B is 14 m/s
Explanation:
Given that:
mass of the block slides = 1.5 - kg
height = 10 m
Force constant = 200 N/m
distance of rough surface patch = 20 m
coefficient of kinetic friction = 0.15
In order to determine the speed of the block when it reaches point B.
We consider the equation for the energy conservation in the system which can be represented by:
v = 14 m/s
Thus; the speed of the block when it reaches point B is 14 m/s
Explanation: Formulas you need to use:
K=0.5mass(Velocity^2)
km/h / 3.6 ===>M/S
Step 1:
convert km/h to m/s
Put the values in the formula :
Answer:
.D)The Vector sum of the linear momenta of the fragments must be zero.
Explanation:
.D)The Vector sum of the linear momenta of the fragments must be zero.
This statement is true. This is so because no external force is acting on the masses. The motion is created by internal force so momentum of fragments will be conserved.
A) this statement is false because kinetic energy was zero in the beginning ( the bomb was stationary in the beginning )
B ) This statement is false because it violates the law of conservation of momentum .( it does not violates only when all the fragments have equal mass )
C ) This statement is zero because kinetic energy is not a vector quantity so two kinetic energy when added can not sum up to zero.
