The number of mole of aluminum chloride, AlCl₃ produced when 5 moles of chlorine gas, Cl₂ reacts is 3.33 moles
<h3>Balanced equation </h3>
2Al(s) + 3Cl₂(g) → 2AlCl₃(s)
From the balanced equation above,
3 moles of Cl₂ reacted to produce 2 moles of AlCl₃.
<h3>How to determine the moles of AlCl₃ produced </h3>
From the balanced equation above,
3 moles of Cl₂ reacted to produce 2 moles of AlCl₃.
Therefore,
5 moles of Cl₂ will react to = (5 × 2) / 3 = 3.33 moles of AlCl₃.
Thus, 3.33 moles of AlCl₃ were obtained from the reaction.
Learn more about stoichiometry:
brainly.com/question/14735801
