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Lesechka [4]
2 years ago
11

1.-A mixture of aluminum metal and chlorine gas reacts to form aluminum chloride (AlCl3): 2Al(s) +

Chemistry
1 answer:
Alika [10]2 years ago
5 0

The number of mole of aluminum chloride, AlCl₃ produced when 5 moles of chlorine gas, Cl₂ reacts is 3.33 moles

<h3>Balanced equation </h3>

2Al(s) + 3Cl₂(g) → 2AlCl₃(s)

From the balanced equation above,

3 moles of Cl₂ reacted to produce 2 moles of AlCl₃.

<h3>How to determine the moles of AlCl₃ produced </h3>

From the balanced equation above,

3 moles of Cl₂ reacted to produce 2 moles of AlCl₃.

Therefore,

5 moles of Cl₂ will react to = (5 × 2) / 3 = 3.33 moles of AlCl₃.

Thus, 3.33 moles of AlCl₃ were obtained from the reaction.

Learn more about stoichiometry:

brainly.com/question/14735801

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After the first steps in writing an equation, the equation is balanced by
kifflom [539]

Answer:

law of conservation of mass

Explanation:

self explanatory

5 0
3 years ago
Which of the following will decrease the frequency of collisions?
kogti [31]

Answer:

The question isn't worded properly, but if 1 or 2 are DECREASED, the frequency of collisions of specified molecules will decrease.

Explanation:

Catalysts only facilitate reaction once molecules collide. Increased temperature makes molecules move more, and thus collide more. For concentration, if there are more molecules in the same amount of room/liquid, there will be more collisions because there are more of the molecules to collide.

8 0
3 years ago
A 50.0 mg sample of iodine-131 was placed in a container 32.4 days ago. if its half-life is 8.1 days, how many milligrams of iod
sertanlavr [38]

3.124mg of I-131 is present after 32.4 days.

The 131 I isotope emits radiation and particles and has an 8-day half-life. Orally administered, it concentrates in the thyroid, where the thyroid gland is destroyed by the particles.

What is Half life?

The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.

Half of the iodine-131 will still be present after 8.1 days.

The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.

The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.

If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.

Learn more about the Half life of radioactie element with the help of the given link:

brainly.com/question/27891343

#SPJ4

7 0
1 year ago
Scientist can use the of minerals to tell them apart A.sound B.length C.size D.color
ipn [44]

Answer:

color

Explanation:

Scientists can use the color of minerals to tell them apart.

7 0
3 years ago
Physical science!!!please help me !!!
Anestetic [448]

Answer:

number 4

Explanation:

3 0
2 years ago
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