Answer:
2Fe2 S3+6O2 → 2Fe2O3+3SO2
Explanation:
Answer:
![pH=-1.37](https://tex.z-dn.net/?f=%20pH%3D-1.37)
Explanation:
We are given that 25 mL of 0.10 M
is titrated with 0.10 M NaOH(aq).
We have to find the pH of solution
Volume of ![CH_3COOH=25mL=0.025 L](https://tex.z-dn.net/?f=CH_3COOH%3D25mL%3D0.025%20L)
Volume of NaoH=0.01 L
Volume of solution =25 +10=35 mL=![\frac{35}{1000}=0.035 L](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B1000%7D%3D0.035%20L)
Because 1 L=1000 mL
Molarity of NaOH=Concentration OH-=0.10M
Concentration of H+= Molarity of
=0.10 M
Number of moles of H+=Molarity multiply by volume of given acid
Number of moles of H+=
=0.0025 moles
Number of moles of
=0.001mole
Number of moles of H+ remaining after adding 10 mL base = 0.0025-0.001=0.0015 moles
Concentration of H+=![\frac{0.0015}{0.035}=4.28\times 10^{-2} m/L](https://tex.z-dn.net/?f=%5Cfrac%7B0.0015%7D%7B0.035%7D%3D4.28%5Ctimes%2010%5E%7B-2%7D%20m%2FL)
pH=-log [H+]=-log [4.28
]=-log4.28+2 log 10=-0.631+2
![pH=-1.37](https://tex.z-dn.net/?f=%20pH%3D-1.37)
The answer to your question is D!
Molecular equation
Hg₂(NO₃)₂ (aq) + KI(aq) ⇒Hg₂I₂(s) + 2KNO₃(aq)
Total Ionic equation
Hg²⁺(aq) + 2NO³⁻(aq) + 2K⁺aq) ⇒Hg₂I₂(s) + 2K⁺(aq) + NO³⁻ (aq)
Net Ionic equation
Hg²⁺(aq) + 2I⁻(aq) ⇒ Hg₂I₂(s)
<h3>What is the molecular equation?</h3>
Sometimes, a balanced equation is all that is used to refer to a chemical equation. Any ionic substances or acids are represented using their chemical formulas as neutral compounds in a molecular equation. Each substance's state is described in parenthesis after the formula. A complete ionic equation also contains the spectator ions, whereas a net ionic equation just displays the chemical species that are involved in a reaction.
The steps listed below can be used to determine the net ionic equation for a specific reaction:
Include the states of each chemical in the balanced molecular equation for the reaction.
To know more about the molecular equation, visit:
brainly.com/question/14286552
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