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nataly862011 [7]
3 years ago
11

What is unique about the nitrogen family

Chemistry
2 answers:
ankoles [38]3 years ago
7 0
Nitrogen molecule is diatomic, whereas other elements form tetraatomic molecules.
attashe74 [19]3 years ago
7 0
The molecules and cells make up of one big badonleydonk so that’s why they all connect
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A copper atom has a mass of 1 06 times 10^-22 g and a penny has a mass of 2.5 g. Use this information to answer the questions be
amm1812

Answer:

Mass of 1 mole of copper is 63.83 g.

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

Explanation:

Mass of 1 copper atom,m = 1.06\times 10^{-22} g

1 mole = 6.022\times 10^{23} atoms

Mass of 1 mole of copper :

= 6.022\times 10^{23} atoms\times 1.06\times 10^{-22} g=63.83 g

Mass of 1 mole of copper = 63.83 g

Mass of copper penny = 2.5 g

Atomic mass of copper = 63.83 g/mol

Moles of copper in 2.5 g of copper penny:

\frac{2.5 g}{63.83 g/mol}=0.03916 mol

0.03916 moles of copper atoms have a mass equal to the 2.5 grams of copper penny.

8 0
3 years ago
What intermolecular forces occur between two methane molecules?
nikklg [1K]
<span><span>Dipole-dipole interactions , example: ammoni </span><span>forces, example: methane, CH4</span><span>Hydrogen bonding example: water, H2O </span></span>
4 0
3 years ago
Concentrated HCl is 37% m/m. The density of the solution is 1.19 g/mL. Assume you have 100.0 grams of SOLUTION.
sdas [7]

Answer:

M HCl sln = 12.0785 M

Explanation:

  • molarity (M) [=] mol/L
  • %mm = ((mass compound)/(mass sln))*100

∴ mass sln = 100.0 g

∴ δ sln = 1.19 g/mL

∴ % m/m = 37 %

⇒ 37 % =((mass HCl/mass sln))*100

⇒ 0.37 = mass HCl / 100.0 g

⇒ 37 g = mass HCl

∴ molar mass HCl = 36.46 g/mol

⇒ mol HCl = (37 g)*(mol/36.46 g) = 1.015 mol

⇒ volume sln = (100 g sln)*(mL/1.19 g) =  84.034 mL = 0.084034 L

⇒ M HClsln = 1.015 mol/0.084034 L

⇒ M HCl sln = 12.0785 M

7 0
3 years ago
How to classify hemicetal and acetal
kumpel [21]
You might have meant hemiacetal, not hemicetal.
Acetals contain two –OR groups, one –R group and a –H atom. In hemiacetals, one of the –OR groups in acetals is replaced by a –OH group<span>.
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3 0
3 years ago
Give the formula for an ionic compound formed from each pair of ions
Vera_Pavlovna [14]

Please, find the complete question in the picture attached.

Answer:

1. Na₂O

2. AlF₃

3. MgO

4. Ca₃P₂

Explanation:

1. Na⁺ and O²⁻

An ionic compound will be formed when two ions of opposite charge attract each other.

The positive ion is called cation and the negative ion is called anion.

Thus, every ionic compound has a cation and an anion electrostatically bonded.

The ions must combine in a proportion that genders a neutral compound: so you must have as many cations as negative charge has one anion and as many anions as positive charge has one cation.

This is, if the cation has charge +x, there will be x anions, and if the anion has charge -y, there will be y cations.

Simbolically:

Cation:A^{+x}\\ \\ Anion:B^{-y}\\ \\ Compound:A_yB_x

As you see, the subscripts for each element in the chemical formula are obtained by the exchage of the charges of the ions.

Then, for Na⁺ and O²⁻, the subscript for Na will be 2 and the subscript for O will be 1; and the formula of the ionic compound formed by this pair ot ions is:

  • Na₂O

2. Al³⁺ and F⁻

  • The subscript of Al will be 1 (because the F ion has charge 1-, and the subscript of F will be 3 (because the Al ion has charge +3).

Thus the ionic compound formed by this pair of ions is:

  • AlF₃

3. Mg²⁺ and S²⁻

  • The charge 2+ from Mg atom wil become the subscript 2 of S atom, and the charge 2- will become the subscript 2 of Mg atom:

That results in the formula: Mg₂S₂

Except for some special compounds, the chemical formula is simplified, dividing by the least common denominator. In this case, that means that the two 2 subscripts are simplified to 1, and the final chemical formula for the ionic compound formed by this pair of ions is:

  • MgO

4. Ca²⁺ and P³⁻

  • The charge 2+ from Ca will become subscript 2 for P and the charge 3- whill become subscript 3 for Ca.

Hence, the ionic compound formed by these two ions is:

  • Ca₃P₂

7 0
3 years ago
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