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2 years ago

A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.

Physics

1 answer:

FinnZ [79.3K]2 years ago

4 0

We have that the maximum height reached by the basketball from its release point is

$S=1.3m$

From the question we are told

A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.
What is the maximum height reached by the basketball from its release point?

Generally the Newtons equation for Motion is mathematically given as

$V^2=u^2+2as\\\\Therefore\\\\0=25-19.6*S\\\\S=\frac{25}{19.6}\\\\S=1.276$

$S=1.3m$

Therefore

The maximum height reached by the basketball from its release point is

$S=1.3m$

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Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.

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Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.

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3 years ago

A basketball is tossed upwards with a speed of 5.0 m/s. ​We can ignore air resistance.

A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.