A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.
1 answer:
We have that the maximum height reached by the basketball from its release point is
From the question we are told
- A basketball is tossed upwards with a speed of 5.0 m/s. We can ignore air resistance.
- What is the maximum height reached by the basketball from its release point?
Generally the Newtons equation for Motion is mathematically given as
Therefore
The maximum height reached by the basketball from its release point is
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9514 1404 393
Answer:
- moderate low: 82
- moderate high: 112.75
- vigorous low: 123
- vigorous high: 174.25
Explanation:
When calculations are repetitive, I find it convenient to use a calculator that can work with tables.
The PMHR is (220 -15) = 205.
Each of the other heart rates is computed as the formula shows. For example, the low moderate heart rate is 205×0.40 = <u> 82 </u> bpm
The other rates are shown in the attached table. They are computed the same way.
The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".
According to the question,
Mass of box A,
Mass of box B,
Horizontal force,
From the Newton's law,
→
or,
→
Bu substituting the values, we get
→
→
→
We can see that between the two boxes, the action-reaction pair exist.
then,
→
→
→ (magnitude)
Thus the above solution is appropriate.
Learn more about the magnitude here:
