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lyudmila [28]
3 years ago
5

A single-turn circular loop of wire of radius 45 mm lies in a plane perpendicular to a spatially uniform magnetic field. During

a 0.10 s time interval, the magnitude of the field increases uniformly from 250 to 350 mT. (a) Determine the emf induced in the loop (in V). (Enter the magnitude.) V (b) If the magnetic field is directed out of the page, what is the direction of the current induced in the loop
Physics
1 answer:
Lina20 [59]3 years ago
7 0

Answer:

Magnitude of induced emf is 0.00635 V

Explanation:

Radius of circular loop r = 45 mm = 0.045 m

Area of circular loop A=\pi r^2

A=3.14\times 0.045^2=0.00635m^2

Magnetic field is increases from 250 mT to 350 mT

Therefore change in magnetic field dB=250-350=100mT

Emf induced is given by

e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

e=-0.00635\times \frac{100\times 10^{-3}}{0.10}=-0.00635V

Magnitude of induced emf is equal to 0.00635 V

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A rat runs 2m right, turns around and runs 3m left. Then goes 2m right. What is its displacement?
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An object is pushed from rest across a sheet of ice, accelerating at 8.0 m/s^2 [E] over a displacement of 1.05 m [E]. The object
tatiyna

Answer:

D_T=18.567m

Explanation:

From the question we are told that:

Acceleration a=8.0 m/s^2

Displacement d=1.05 m

Initial time t_1=6.0s

Final Time t_2=2.5s

Generally the equation for Velocity of 1.05 travel is mathematically given by

Using Newton's Law of Motion

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Generally the equation for Distance to stop is mathematically given by

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Therefore

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Generally the Total Distance Traveled is mathematically given by

 D_T=d_1+d_2+d_3

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 D_T=18.567m

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2 years ago
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