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3 years ago

A student is on a balcony 15.6 m above the street. She throws a ball vertically downward at 10.7 m/s.

Physics

1 answer:

andrew11 [14]3 years ago

3 0

Answer:

20.65 m/s

Explanation:

You are gonna wanna use a calculator for this one

so we will write all the known variables:

h = 15.6 m

initial velocity (u) = 10.7 m/s

acceleration (a) = 10 m/s/s (gravity)

From the third equation of motion:

v² - u² = 2ah

v² - (10.7)² = 2(10)(15.5)

v² - (10.7)² = 312

v² = 312 + 114.49

v² = 426.49

v = 20.65 m/s

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Muscles covert chemicals energy int

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Answer:

Mechanical energy

Explanation:

Mechanical energy is needed for movement of objects. Muscles convert chemical energy provided by the rest of the body to allow movement.

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3 years ago

A merry-go-round of radius 2 m is rotating at one revolution every 5 s. A

galben [10]

Answer:

a) The angular speed of the child is approximately 1.257 rad/s

b) The angular speed of the teenager is approximately 1.257 rad/s

c) The tangential speed of the child is approximately 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager is approximately 2.513 m/s

Explanation:

The revolutions per minute, r.p.m. of the merry-go-round = 1 revolution/(5 s)

The radius of the merry-go-round = 2 m

The location of the child = 1 m from the axis

The location of the teenager = 2 m from the axis

1 revolution = 2·π radians

Therefore, we have;

The angular speed, ω = (Angle turned)/(Time elapsed) = (2·π radians)/(5 s)

∴ The angular speed of the merry-go-round, ω = 2·π/5 radians/second

a) The angular speed of the child = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

b) The angular speed of the teenager = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

c) The tangential speed, v = r × The angular speed, ω

Where;

r = The radius of rotation of the object

For the child, r = 1 m

The tangential speed of the child = 1 m × 2·π/5 radians/second = 2·π/5 m/s ≈ 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager = 2 m × 2·π/5 radians/second = 4·π/5 m/s ≈ 2.513 m/s

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2 years ago

Describe how the smoke particles move when a candle was blown out?

lukranit [14]

Answer:

When a candle was blown out, the flame stops immediately but the wick and the wax are both still hot, so pyrolysis continues for a few seconds. Explanation:

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2 years ago

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s 1045 rad/s ). If a particular disk is

Scilla [17]

Answer:

The magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

Explanation:

Given that,

Angular velocity, $\omega_i=968.7\ rad/s$

The disk comes to rest, $\omega_i=0$

Time, t = 0.234 s

We need to find the magnitude of the average angular acceleration of the disk. It is given by change in angular velocity per unit time. So,

$\alpha =\dfrac{\omega f}{t}\\\\\alpha =\dfrac{968.7\ rad/s}{0.234\ s}\\\\\alpha =4139.74\ rad/s^2$

So, the magnitude of the average angular acceleration of the disk is $4139.74\ rad/s^2$ .

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3 years ago

use the instantaneous center of zero velocity to determine the angular velocity !ab of link ab and the velocity vb of collar b f

allsm [11]

Instantaneous center:

It is the center about a body moves in planer motion. The velocity of Instantaneous center is zero and Instantaneous center can be lie out side or inside the body. About this center every particle of a body rotates.

From the diagram

Where these two lines will cut then it will the I-Center.Point A and B is moving perpendicular to the point I.

If we take three link link1,link2 and link3 then I center of these three link will be in one straight line It means that they will be co-linear.

Therefore, when the mass is at its equilibrium position (which corresponds to x=0), the velocity of the mass will be maximum.

To know more about velocity, refer: brainly.com/question/12413963

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1 year ago