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grigory [225]
2 years ago
11

What is the kinetic energy of a 3000kg object moving at a velocity of 300m/s?

Physics
2 answers:
Savatey [412]2 years ago
6 0

Answer:

  • <u>135000000 Joules</u>

Explanation:

Here we are given Mass of the object is 3000 kg and velocity is 300 m/s. and we need to calculate the Kinetic energy.

Formula of Kinetic energy is given by:

\: \: \: \: \dashrightarrow \: \: \: { \underline{ \boxed{ \sf{KE = \dfrac{1}{2} mv^2 }}}}

Where,

  • m is mass
  • v is velocity

On substituting the required values in above formula, we get:

\\ \: \: \: \dashrightarrow \: \: \:  \sf KE = \dfrac{1}{2} \times 3000 \times (300)^2 \\ \\ \\ \: \: \: \dashrightarrow \: \: \:  \sf KE = \dfrac{1}{2} \times 3000 \times 90000 \\ \\ \\ \: \: \: \dashrightarrow \: \: \:  \sf KE = \dfrac{1} {\cancel{{2}}} \times { \cancel{3000}} \times 90000 \\ \\  \\ \: \: \: \dashrightarrow \: \: \:  \sf KE =1500 \times 90000 \\ \\ \\ \: \: \: \dashrightarrow \: \: \:  {\underline{\boxed{\sf{ KE =135000000 \: J}}}} \\ \\ \\

  • Kinetic energy is 135000000 Joules
zvonat [6]2 years ago
5 0

Answer:

\sf {\Large{ \purple{The  \: kinetic \:  energy  \: of \:  the \:  object \:  is \: 1.35 \times  {10}^{8}J }}}

Explanation:

\textsf{ \underline{ \red{ \large{To find :-}}}}

The kinetic energy of a moving object

\textsf{ \underline{ \pink{ \large{Given :-}}}}

Mass of the object (m) = 3000kg

velocity of the object (v) = 300m/s

\textsf{ \huge{ \underline{ \underline{ \blue{Solution :-}}}}}

\sf Kinetic \:  energy  \: (K.E.) =  \frac{1}{2} m {v}^{2}  \\  \sf K.E. =  \frac{1}{2}  \times 3000 \times  {300}^{2} \\  \sf  K.E. =  \frac{1}{2}  \times 3000 \times 300 \times 300 \\ \sf K.E. = 3000 \times 300 \times 150 \\  \sf K.E. = 135,000,000 \\ \textsf{(J = joule)}  \\  \sf{ \green{ K.E. = 1.35 \times  {10}^{8}J }}

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umka2103 [35]

Answer:

B = 0.024T positive z-direction

Explanation:

In this case you consider that the direction of the motion of the electron, and the direction of the magnetic field are perpendicular.

The magnitude of the magnetic force exerted on the electron is given by the following formula:

F=qvB     (1)

q: charge of the electron = 1.6*10^-19 C

v: speed of the electron = 1.6*10^7 m/s

B: magnitude of the magnetic field = ?

By the Newton second law you also have that the magnetic force is equal to:

F=qvB=ma       (2)

m: mass of the electron = 9.1*10^-31 kg

a: acceleration of the electron = 7.0*10^16 m/s^2

You solve for B from the equation (2):

B=\frac{ma}{qv}\\\\B=\frac{(9.1*10^{-31}kg)(7.0*10^{16}m/s^2)}{(1.6*10^{-19}C)(1.6*10^7m/s)}\\\\B=0.024T

The direction of the magnetic field is found by using the right hand rule.

The electron moves upward (+^j). To obtain a magnetic forces points to the positive x-direction (+^i), the direction of the magnetic field has to be to the positive z-direction (^k). In fact, you have:

-^j X ^i = ^k

Where the minus sign of the ^j is because of the negative charge of the electron.

Then, the magnitude of the magnetic field is 0.024T and its direction is in the positive z-direction

8 0
3 years ago
Two long parallel wires are separated by forty centimeters and carry oppositely-directed currents of ten amperes. Find the magni
Softa [21]

Answer:

1.04μT

Explanation:

Due to both wires have opposite currents, the magnitude of the total magnetic field is given by

B_T=\frac{\mu_o I}{2 \pi r_1}-\frac{\mu_o I}{2 \pi r_2}

I: electric current = 10A

mu_o: magnetic permeability of vacuum = 4pi*10^{-7} N/A^2

r1: distance from wire 1 to the point in which B is measured.

r2: distance from wire 2.

The distance between wires is 40cm = 0.4m. Hence, r1=0.2m r2=0.6m

By replacing in the formula you obtain:

B_T=\frac{(4\pi *10^{-7}N/A^2)(10A)}{2\pi}(\frac{1}{0.4m}-\frac{1}{0.6m})=1.04*10^{-6}T =1.04\mu T

hence, the magnitude of the magnetic field is 1.04μT

4 0
3 years ago
It is claimed that if a lead bullet goes fast enough, it can melt completely when it comes to a halt suddenly, and all its kinet
Amiraneli [1.4K]

Answer:

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Explanation:

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c = specific heat of lead = 128 J/(kg °C)

L = Latent heat of fusion of lead = 24500 J/kg

T_{i} = initial temperature = 27.4 °C

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v = Speed of lead bullet

Using conservation of energy

Kinetic energy of bullet = Heat required for change of temperature + Heat of melting

(0.5) m v^{2} = m c (T_{f} - T_{i}) + m L\\(0.5) v^{2} = c (T_{f} - T_{i}) + L\\(0.5) v^{2} = (128) (327.5 - 27.4) + 24500\\(0.5) v^{2} = 62912.8\\v = 354.72 ms^{-1}

3 0
3 years ago
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Archy [21]

Answer:

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Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

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Use formula:

  • \boxed{\bold{T=m*g}}

Replace and solve:

  • \boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}
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The tension in the rope is <u>98 Newtons.</u>

Greetings.

5 0
3 years ago
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Butoxors [25]
X = v * t
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