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tensa zangetsu [6.8K]
2 years ago
7

A vehicle of mass 100kg has a kinetic energy of 5000 J at an instant. The velocity at that instant is​

Physics
2 answers:
snow_lady [41]2 years ago
7 0

Answer:

  • \bf\pink{10\:m/s}

Explanation:

<h2><u>Given</u> :-</h2>

  • \sf\red{Mass \ of \ vehicle \ (m) = 100 \ kg}
  • \sf\orange{Kinetic \ energy \ (K.E.) = 5000 \ J}

<h2><u>To Find</u> :-</h2>

  • \sf\green{Velocity\: of\: the \:vehicle \:at \:the \:instant}

<h2><u>Formula to be used</u> :-</h2>

  • \sf\blue{K.E. = \dfrac{1}{2} mv^{2}}

Where,

  • K.E. = Kinetic energy possessed by the body
  • M = Mass of the body
  • V = Velocity of the body

<h2><u>Solution</u> :-</h2>

\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}

\to\:\:\sf\orange{5000 = \dfrac{1}{2} \times 100 \times v^{2}}

\to\:\:\sf\green{5000 = 50 \times v^{2}}

\to\:\:\sf\blue{\dfrac{5000}{50} = v^{2}}

\to\:\:\sf\purple{100 = v^{2}}

\to\:\:\sf\red{\sqrt{100} = v}

\to\:\:\sf\orange{ 10 = v}

\to\:\:\bf\pink{v = 10\:m/s}

  • Velocity of the vehicle at the instant is \bf\green{10\:m/s}
Nikolay [14]2 years ago
5 0

Answer:

23.51 m/s

Explanation:

Parameters given:

Kinetic energy, K = 295 J

Momentum, p = 25.1 kgm/s

a) The kinetic energy of a body is given as:

where m = mass of the body and v = speed of the body

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If an object is thrown upward with an initial velocity of 128 ​ft/second, then its height after t seconds is given by the follow
IrinaK [193]

Answer:

The maximum height attained by the object and the number of seconds are 128 ft and 4 sec.

Explanation:

Given that,

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Equation of height

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(a). We need to calculate the maximum height

Firstly we need to calculate the time

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From equation (I)

\dfrac{dh}{dt}=128-64t

128-64t=0

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Now, for maximum height

Put the value of t in equation (I)

h =128\times2-32\times4

h=128\ ft

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We know that, when the object reaches ground the height becomes zero

128t-32t^2=0

t(128-32t)=0

128=32t

t=4\ sec

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3 years ago
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Please help me
Grace [21]

Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

6 0
2 years ago
A typical wall outlet voltage is 120 volts in the United States. Personal MP3 players require much smaller voltages, typically 2
butalik [34]

Answer:        

Number of turns in secondary will be 7

Explanation:

We have given primary voltage V_p=120volt

Number of turns in the primary is N_p=3575

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We have to find the number of turns in secondary

We know that \frac{N_p}{N_s}=\frac{V_p}{V_s}

So \frac{3575}{N_s}=\frac{120}{0.235}

N_s=6.60

As the number of turns can not be in decimal so number of turns will be 7

6 0
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