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3 years ago

{WILL GIVE (Brain lies t) TO FULL ANSWERS}

Physics

2 answers:

Nataly_w [17]3 years ago

5 0

Answer:

1. Their temperature and luminascity

2. The sun

3. Main sequence (im not sure of the answer tho)

4. Because of the color the white dwarfs are white and the sun in and orange/red color

5. Blue giants

<em>~I hope this helps! Peace :D</em>

kap26 [50]3 years ago

4 0

Answer:

1: surface temperature

2: red giant

3: The brightest stars are called supergiants. Star clusters are rich in stars just off the main sequence called red giants. Main sequence stars are called dwarfs.

4: A white dwarf is very dense

5: red giant

plz mark me as brainliest :)

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How much pressure is created when you apply a

Alekssandra [29.7K]

Pressure
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=0.126 m2
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1 year ago

A student forms the following hypothesis if people wear bright colors, they will be happier. What is/are the problems with this

mars1129 [50]

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3 years ago

Children in a tree house lift a small dog in a basket 4.00 m up to their house. If it takes 187 J of work to do this, what is th

Vika [28.1K]

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F - force
h - distance

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3 years ago

Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars

zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

$T^2 \propto R^3$

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

$T^2 \propto R^3$

$T^2 = kR^3$

Substituting the values, we get the value of constant k for mars.

$687^2 = k\times (2.279 \times 10^{11})^3$

$k = 3.92 \times 10^{-29}$

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

$365^3 = 3.92\times 10^{-29} R^3$

$R^3 = 3.39 \times 10^{33}$

$R= 1.50 \times 10^{11}\;\rm m$

Hence we can conclude that the distance of the earth from the sun is $1.50 \times 10^{11}\;\rm m$ .

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

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2 years ago

A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-

Alisiya [41]

First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
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the angular speed is
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And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
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3 years ago