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igomit [66]
1 year ago
8

A copper block rests 30.0 cm from the center of a steel turntable. The coefficient of static friction between the block and the

surface is 0.53. The turntable starts from rest and rotates with a constant angular acceleration of 0.50 rad/s2. After what time interval will the block start to slip on the turntable?
pls explain the question briefly
Physics
1 answer:
PIT_PIT [208]1 year ago
3 0

Answer:

refer to the above attachment

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Can some one please help me with 7 and 8 I can’t fail this I’ll mark brainless .
Musya8 [376]
I think the first question is talking about the ionic compound Sodium sulfide and it’s formula is Na2S.
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3 years ago
Balboa Park in San Diego has an outdoor organ. When the air temperature increases, the fundamental frequency of one of the organ
musickatia [10]

The fundamental frequency of one of the organ pipes will go up or increase.

When pressured air is forced into an organ pipe, it echoes at a particular pitch, generating the sound of the pipe organ. Each pipe has been adjusted to a particular pitch on the musical scale.

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The correct option is (c).

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brainly.com/question/254161

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6 0
1 year ago
Something that claims to be science but is not is called
icang [17]
That is called pseudoscience
5 0
3 years ago
Given a volume of 1000. Cm^3 of an ideal gas at 300 k, what volume would iy occupy at a temperature of 600 k
LUCKY_DIMON [66]

Answer:2000 cm³

Here, pressure remains constant.

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8 0
3 years ago
A 5.00X10^5 kg rocket is accelerating straight up. Its engines produce 1.250X10^7 N of thrust, and air resistance is 4.50X10^6 N
katrin [286]
<span>6.20 m/s^2 The rocket is being accelerated towards the earth by gravity which has a value of 9.8 m/s^2. Given the total mass of the rocket, the gravitational drag will be 9.8 m/s^2 * 5.00 x 10^5 kg = 4.9 x 10^6 kg m/s^2 = 4.9 x 10^6 N Add in the atmospheric drag and you get 4.90 x 10^6 N + 4.50 x 10^6 N = 9.4 x 10^6 N Now subtract that total drag from the thrust available. 1.250 x 10^7 - 9.4 x 10^6 = 12.50 x 10^6 - 9.4 x 10^6 = 3.10 x 10^6 N So we have an effective thrust of 3.10 x 10^6 N working against a mass of 5.00 x 10^5 kg. We also have N which is (kg m)/s^2 and kg. The unit we wish to end up with is m/s^2 so that indicates we need to divide the thrust by the mass. So 3.10 x 10^6 (kg m)/s^2 / 5.00 x 10^5 kg = 0.62 x 10^1 m/s^2 = 6.2 m/s^2 Since we have only 3 significant figures in our data, the answer is 6.20 m/s^2</span>
8 0
3 years ago
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