2 Use the chart to answer the question. Solubility Curves of Various Salts 180 160 140 120 100 80 KNO3 in g NaCl in g KCl in g A
mount of Solute Dissolved in 100 g of Water (grams) 60 40 20 20 40 60 80 100 1200 20 Temperature (°C) If a student makes a saturated solution of potassium nitrate at 80°C, then cools it to 20°C, how many grams of solute would precipitate out of the solution? MO A B C D 10 g 20 g 60 g 140 g
According to the information in the graph, it can be inferred that the amount of solute that will precipitate out of solution at 20°C is 130 grams.
<h3>How to calculate the amount of solute that precipitates out of solution?</h3>
To calculate the amount of solute that precipitates out of solution we must identify the solute data at 80°C and 20°C and identify the difference as shown below:
Quantity of solute at 80°C: 170 grams.
Quantity of solute at 20°C: 40 grams.
170 grams - 40 grams = 130 grams
According to the above, the amount of solute that will precipitate out of solution due to the change in temperature is 130 grams of KNO3.
Note: This question is incomplete because the graph is missing. Here is the graph
1. The <span>student with a measurement that might be in centimeters is A. Bill. 2. C</span><span>entimeters in 0.05 kilometers is</span>C. 5,000 solution: 0.05 km x (1000 meters/ 1 km) = 50 meters x (100 cm/ 1 meter) =5000 cm