Question

The mass of an average blueberry is 0.75 g and the of am automoblie is 2.0 x 10 to the 3 Kg. Find the number of automobiles whose total mass is the same as 1.0 mole of blueberries.

Answer 1

Answer : The number of automobiles needed are, $2.26\times 10^{17}$

Explanation :

First we have to calculate the mass of blueberries.

As, 1.0 mole of blueberries contains $6.022\times 10^{23}$ blueberries

So, 0.75 grams of blueberries contains $0.75g\times 6.022\times 10^{23}=4.52\times 10^{23}g$ blueberries

Mass of blueberries = $4.52\times 10^{23}g$

Now we have to calculate the number of automobiles needed.

Number of automobiles needed = $\frac{4.52\times 10^{23}g}{2.0\times 10^{3}kg}$

Number of automobiles needed = $\frac{4.52\times 10^{23}g}{2.0\times 10^{3}\times 10^{3}g}$

Number of automobiles needed = $2.26\times 10^{17}$

Thus, the number of automobiles needed are, $2.26\times 10^{17}$