Answer:
133/143
Step-by-step explanation:
Let S be the sample space
Let E be the event of selecting three committee partners with at least one junior partner.
Partners in the law firm include:
Senior partners = 6
Junior partners = 7
Total partners = 13
n(S) = number of ways of selecting 3 partners from 13 = 13C3
n(S) = 13C3 = 13!/(10!3!) = (13x12x11)/(3x2x1) = 286
To get n(E) i.e least 1 junior partner in the selected committee, we may have:
(2 senior and 1 junior) or ( 1 senior and 2 junior) or (3 junior).
Therefore, the required number of way is given below:
= (6C2 x 7C1) + (6C1 x 7C2) + 7C3
= [(6x5)/2 x 7] + [6 x (7x6)/2] + [(7x6x5)/(3x2)]
= 105 + 126 + 35
n(E) = 266
Therefore, the probability P(E) that at least one of the junior partners is on the committee is given below:
P(E) = n(E) /n(S)
P(E) = 266/286
P(E) = 133/143
In here, we could write an equality as x – 12 < 65. In solving inequalities, we follow the same rule as solving algebraic expressions. We will transpose 12 to the other side, giving us x < 65 + 12. Simplifying, we have x < 77. Geraldo must have a bill less than $77 in order for him not to spend more than $65.
Answer:
$13.50
Step-by-step explanation:
First, we got to multiply $18 by 25% or .25
$18 x .25 = $4.50
Lastly, we just subtract $4.50 from $18.
$18 - $4.50 = $13.50
