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2 years ago

8

A cue ball of inertia m is given a speed v before it collides elastically with a full rack of 15 stationary balls in a game of p

ool. Each of the 16 balls has an inertia m.

1 answer:

Stels [109]2 years ago

7 0

The final speed of the 15 stationary balls in a game of pool is determined as the ratio of inertia of the cue ball to total mass of the 15 balls.

<h3>Final speed of the 15 balls</h3>

The final speed of the 15 balls can be determined by applying the principle of conservation of linear momentum as shown below;

J = ΔP

where;

J is inertia
ΔP is change in momentum

m1u1 + m0u0 = m1v1 + m0v0

where;

m1 is mass of the cue ball
m0 is mass of the 15 balls
u is initial velocity
v is final velocity

m1u1 - 0 = m1v1 + 15mv0

m1u1 - m1v1 = 15mv0 - 0

recall, m1u1 - m1v1 = ΔP = J

-m = 15m0v0

v0 = -m/15m0

where;

v0 is the final speed of the 15 balls
15m0 is the total mass of the 15 balls
m is the inertia of the cue ball

Thus, the final speed of the 15 stationary balls in a game of pool is determined as the ratio of inertia of the cue ball to total mass of the 15 balls.

Learn more about linear momentum here: brainly.com/question/7538238

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Answer:

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3 years ago

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The elastic potential energy (Ep) is given by $Ep = \frac{1}{2}*k*x^2$

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Ep = ? (Joule)
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Solving:
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3 years ago

The figure shows a 100-kg block being released from rest from a height of 1.0 m. It then takes it 0.90 s to reach the floor. Wha

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Answer:

The mass of the another block is 60 kg.

Explanation:

Given that,

Mass of block M= 100 kg

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Let the mass of the other block is m.

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Using equation of motion

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$Ma=Mg-T$

$T=Mg-Ma$ ....(I)

The net force of the block m

$ma=T-mg$

Put the value of T from equation (I)

$ma=Mg-Ma-mg$

$m(a+g)=M(g-a)$

$m=\dfrac{M(g-a)}{(a+g)}$

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3 years ago