1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
den301095 [7]
2 years ago
8

A cue ball of inertia m is given a speed v before it collides elastically with a full rack of 15 stationary balls in a game of p

ool. Each of the 16 balls has an inertia m.
Physics
1 answer:
Stels [109]2 years ago
7 0

The final speed of the 15 stationary balls in a game of pool is determined as the ratio of inertia of the cue ball to total mass of the 15 balls.

<h3>Final speed of the 15 balls</h3>

The  final speed of the 15 balls can be determined by applying the principle of conservation of linear momentum as shown below;

J = ΔP

where;

  • J is inertia
  • ΔP is change in momentum

m1u1 + m0u0 = m1v1 + m0v0

where;

  • m1 is mass of the cue ball
  • m0 is mass of the 15 balls
  • u is initial velocity
  • v is final velocity

m1u1 - 0 = m1v1 + 15mv0

m1u1  - m1v1 = 15mv0 - 0

recall, m1u1  - m1v1  = ΔP = J

-m = 15m0v0

v0 = -m/15m0

where;

  • v0 is the final speed of the 15 balls
  • 15m0 is the total mass of the 15 balls
  • m is the inertia of the cue ball

Thus, the final speed of the 15 stationary balls in a game of pool is determined as the ratio of inertia of the cue ball to total mass of the 15 balls.

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

You might be interested in
A resistor resists the flow of electricity and usually converts electrical energy to heat energy. True or False?
Sidana [21]
Your answer is: True!
7 0
3 years ago
Read 2 more answers
If a football player collides with a goal post, what forces are at work?
AlekseyPX
When a footballer collides with the goal post, the forces at work are the action and reaction forces. The player will exert an action force on the goal post, and then a reaction force from the goal post will stop the player. The reaction force call will cause pain and even injury to the player.
7 0
3 years ago
How do your results from ray tracing compare to your results from using the thin-lens equation?
EastWind [94]

Answer:

20cm

Explanation:

A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image <em>(image distance can be negative or positive depending on the nature of the image</em>).

According to the lens equation

\frac{1}{f} = \frac{1}{u} + \frac{1}{v} where;

f is the focal length  of the lens

u is the object distance

v is the image distance

If the magnification is - 0.6

mag = v/u = -0.5

v = -0.5u

since v = 10cm

10 = -0.5u

u = -10/0.5

u =-20 cm

Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm

Hence the focal length of the convex lens is 20cm

7 0
3 years ago
Two vectors are presented as a=3.0i +5.0j and b=2.0i+4.0j find (a) a x b, ab (c) (a+b)b and (d) the component of a along the dir
Svet_ta [14]
Let's ask this question step by step:
 Part A) 
 a x b = (3.0i + 5.0j) x (2.0i + 4.0j) = (12-10) k = 2k
 ab = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
 Part (c)
 (a + b) b = [(3.0i + 5.0j) + (2.0i + 4.0j)]. (2.0i + 4.0j)
 (a + b) b = (5.0i + 9.0j). (2.0i + 4.0j)
 (a + b) b = 10 + 36
 (a + b) b = 46
 Part (d)
 comp (ba) = (a.b) / lbl
 a.b = (3.0i + 5.0j). (2.0i + 4.0j) = 6 + 20 = 26
 lbl = root ((2.0) ^ 2 + (4.0) ^ 2) = root (20)
 comp (ba) = 26 / root (20)
 answer
 2k
 26
 46
 26 / root (20)
3 0
3 years ago
2.5 g of helium at an initial temperature of 300 K interacts thermally with 9.0 g of oxygen at an initial temperature of 620 K .
muminat

Answer:

Explanation:

2.5 g of He = 2.5 / 4  mole

= .625 moles

9 g of oxygen = 9/32

= .28 mole of oxygen

C_p of He = 3/2 R

C_p of O₂ = 5/2 R

A ) Initial thermal energy of He = 3/2 n R T

= 1.5 x .625 x 8.32 x 300

= 2340 J

Initial thermal energy of O₂ = 5/2 n R T

= 2.5 x .28 x 8.32 x 620

= 3610.88 J

B ) If T be the equilibrium temperature after mixing

gain of heat by helium

= n C_p Δ T

= .625 x 3/2 R x ( T - 300 )

Loss of heat by oxygen

n C_p Δ T

= .28 x 5/2 R x ( 620 - T )

Loss of heat = gain of heat

.625 x 3/2 R x ( T - 300 ) = .28 x 5/2 R x ( 620 - T )

1.875 T- 562.5 = 868- 1.4 T

3.275 T = 1430,5

T = 436.8 K

Thermal energy of He

= 1.5 x .625 x 8.32 x 436.8

= 3407 J

thermal energy of O₂

= 2.5 x .28  x 8.32 x 436.8

= 2543.92 J

C )

Heat energy transferred

=  .28 x 5/2 R x ( 620 - T )

=  .28 x 5/2 x  8.32 x ( 620 - 436.8 )

1066.95 J

Heat will flow from O₂ to He

Final temperature is 436.8 K

7 0
3 years ago
Other questions:
  • Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel an
    11·1 answer
  • A hollow spherical iron shell floats almost completely submerged in water. The outer diameter is 58.2 cm, and the density of iro
    9·1 answer
  • Amy has a mass of 30 kg, and she is riding a skateboard traveling 5 m/s. What is her momentum
    9·2 answers
  • Using a 1-kW heater for one hour consumes more energy than using a 100-W bulb for twenty-four hours. Please select the best answ
    15·1 answer
  • How much kinetic energy does a baseball with a mass of 0.143 kg have it it is traveling at a velocity of 41.1 m/s?
    8·1 answer
  • Sunlight is used in a double-slit interference experiment. The fourth-order maximum for a wavelength of 490 nm occurs at an angl
    14·1 answer
  • PLEASE HELP! TRUE OR FALSE!
    12·2 answers
  • Does it take more force to slow something down than to speed it up.
    15·1 answer
  • Describe sound and record​
    14·2 answers
  • Which part of the neuron receives messages from other neurons?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!