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aliina [53]
2 years ago
9

Which variable mentioned in Table 2-1 is kept constant? a. amount of time spent swimming b. type of swimming stroke c. number of

calories used d. the person swimming

Physics
1 answer:
Vladimir [108]2 years ago
7 0

Answer:

a. amount of time spent swimming

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How do I do these? My teacher didn’t show us how.
melisa1 [442]

Explanation:

Displacement is simply the change in position.  So in the first part of problem 1, looking at the graph between 0 s and 2 s, the position changes from 0 m to -4 m.  So the displacement is:

Δx =  -4 m − 0 m

Δx = -4 m

Between 2 s and 4 s, the position stays at -4 m.  The displacement is:

Δx = -4 m − (-4 m)

Δx = 0 m

Finally, between 4 s and 6 s, the position goes from -4 m to 6 m.  The displacement is:

Δx = 6 m − (-4 m)

Δx = 10 m

The net displacement is the change in position from 0 s to 6 s:

Δx = 6 m − 0 m

Δx = 6 m

In the second part of problem 1, we have a velocity vs time graph.

Car 1 starts with 0 velocity and ends with a velocity of 6 m/s, so it is accelerating and constantly moving to the right.

Car 2 starts with a velocity of -6 m/s and ends with a velocity of 6 m/s.  It is also accelerating, but first it is moving to the left, comes to a stop at t = 3 s, then moves to the right.

Car 3 starts with a velocity of 2 m/s and ends with a velocity of 2 m/s.  So it is moving constantly to the right, but never speeds up or slows down.

We want to know when two of the cars meet.  Unfortunately, this isn't as easy as looking for where the lines cross on the graph.  We need to calculate their displacements.  We can do this by finding the area under the graph (assuming all the cars start from the same point).

Let's start with Car 2.  Half of the area is below the x-axis, and half is above.  Without doing calculations, we can say the total displacement for this car is 0.  This means it ends back up where it started, and that it never meets either of the other cars, both of which have positive displacements.

So we know Car 1 and Car 3 meet, we just have to find where and when.  For Car 1, the area under the curve is a triangle.  So its displacement is:

Δx = ½ t v(t)

where t is the time and v(t) is the velocity of Car 1 at that time.  Since the line has a slope of 1 and y intercept of 0, we know v(t) = t.  So:

Δx = ½ t²

Now look at Car 3.  The area under the curve is a rectangle.  So its displacement is:

Δx = 2t

When the two cars have the same displacement:

½ t² = 2t

t² = 4t

t² − 4t = 0

t (t − 4) = 0

t = 0, 4

t = 0 refers to the time when both cars are at the starting point, so t = 4 is the answer we're looking for.  Where are the cars at this time?  Simply plug in t = 4 into either of the equations we found:

Δx = 8

So Cars 1 and 3 meet at 4 s and 8 m.

7 0
2 years ago
The path a projectile takes is known as the Question 1 options: vertical component trajectory horizontal component parabola Ques
Firdavs [7]

1. Trajectory

The path a projectile is called a trajectory in physics. It has a vertical component and even makes a parabola, but if we are talking about physics, it is trajectory.

2. A person sitting in a chair

Projectiles can be defined as an object that is in flight. So it has to be in the air. Since a person sitting in a chair is not in flight, then it is NOT a projectile. (Unless you throw the person in the air while he is in the chair)

3. 490 meters

We have the formula and our given:

d = 1/2gt²

Just plug in the values to get your answer:

d = 1/2(-9.8m/s²)(10s)²

d = (-4.9m/s²)(100s²)

d = -490m

So since height is a scalar value, just take out the negative sign.

4. 65 m/s

Again we have our formula and given:

v=\dfrac{d}{t}

So we just plug in our values:

v=\dfrac{650m}{10s}

v=650m/s

5. True

A projectile, if you will notice its trajectory moves both horizontally and vertically. The horizontal motion is what we call the x-component and the vertical is called the y-component. This is what gives it its' curved path.

6. False

An ellipse is an oval-shaped path. A projectile does not move in a circular/oval path. It travels a curved path. It can be parabolic. It is curved but it does not follow a circular path.

7. The vertical component always equals the horizontal component

This is false. Vertical component is different from the horizontal component. The horizontal component is not influenced by gravity only the vertical component. So in short, the horizontal component is the same throughout, but the vertical component changes over time.

8. Constant

Like mentioned above, the horizontal movement is constant or it does not change. This is because a projectile is defined also as an object that is influenced solely by gravity.

9. Vertical velocity decreases

This is because the movement is against the pull of gravity. It will continue to decrease until it will eventually come to a stop and start to descend. As it descends it increases.

10. Vertical velocity increases

I guess explained it above. As the object descends, the vertical movement increases. This is why you can actually die at certain heights. It increases as the time in flight increases. So the longer in flight, the faster it will get.



3 0
3 years ago
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Everybody can you post the lyrics to your favorite song? I'll give brainliest if I know the song or if I like the lyrics, I'll b
andrezito [222]

Answer:

Show and tell

I'm on display for all you (bad word) to see

Show and tell

Harsh words if you don't get a pic with me

Buy and sell (buy and sell me, baby)

Like I'm a product to society

Art don't sell

Unless you (bad word) every authority

Explanation:

4 0
2 years ago
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Work done in taking charge from one point of a conductor to is another point is called ​
Yuliya22 [10]

Answer:

⁸

Explanation:

electric potential

I think so

6 0
2 years ago
an object weighing 15 newtons is lifted from the ground to a height of 0.22 meter what is the increase in the object's gravitati
kicyunya [14]
GPE= weight•height= 15 N• 0.22meter= 3.3 Joules
I hope this helps ~~Charlotte~~
5 0
2 years ago
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