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3 years ago

Is a paper clip a conducted or insulator

1 answer:

5 0

<span>So we want to know is a paper clip a conductor or an insulator. A conductor is a material that doesn't resist very much to the flow of electric current. An insulator is totally oposite of a conductor, it gives a lot of resistane to the flow of electric current. Metals are mostly conductors while rubber, plastics are insulators. Since paper clips are mostly made out of metals, they are a conductor. </span>

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Josh starts at a position of x=0 meters at the left side of the front of the classroom. Over the course of the class he walks ba

Aneli [31]

Answer:
180 meters

Explanation:
Josh walks 6 meters to the right and the 6 meters back. This means that in one time, Josh walks a total distance of 6+6 = 12 meters
Now, we are given that Josh walks this same distance 15 times.
Therefore, we will multiply this distance by 15 to get the total distance that he walks as follows:
Total distance = 12*15 = 180 meters

Based on the above calculations, Josh walks 180 meters over the course of the class

Hope this helps :)

3 0

4 years ago

(Timed) Did I get this physics question right?

morpeh [17]

Answer:

yes

Explanation:

yes that's correct

6 0

3 years ago

Reflecting telescopes are popular because they're

Crank

C. easier to build than a refracting telescope

Big mirrors used in reflecting telescopes are easier and cheaper to make than big lenses which would cost more because of the quality of glass required to make refracting telescopes

6 0

3 years ago

Read 2 more answers

An object is in circular motion. how will the object behave if the centripetal force is removed?

Inessa [10]

The correct answer is

B. it would move in a line tangent to the circular path

In fact, the centripetal force is the only force that keeps the object in a circular trajectory, pulling the object towards the centre of the circle. When this force is removed, there are no other forces acting on the object, therefore for the law of inertia, the object will continue to move at constant velocity, therefore in the same direction (tangent to the circular path) at constant speed.

4 0

4 years ago

Read 2 more answers

Two blocks of clay, one of mass 100 kg and one of mass 3.00 kg, undergo a completely inelastic collision. Before the collision o

adoni [48]

Answer:

a) v = 0.8 m / s , b) $v_{f}$ = 0.777 m / s , c) ΔK = 0.93 J

Explanation:

This exercise can be solved using the concepts of moment, first let's define the system as formed by the two blocks, so that the forces during the crash have been internal and the moment is conserved.

They give us the mass of block 1 (m1 = 100kg, its kinetic energy (K = 32 J), the mass of block 2 (m2 = 3.00 kg) and that it is at rest (v₀₂ = 0)

Before crash

po = m1 vo1 + m2 vo2

po = m1 vo1

After the crash

$p_{f}$ = (m1 + m2) $v_{f}$

a) The initial speed of the block of m1 = 100 kg, let's use the kinetic energy

K = ½ m v²

v = √2K / m

v = √ (2 32/100)

v = 0.8 m / s

b) The final speed,

p₀ = $p_{f}$

m1 v₀1 = (m1 + m2) $v_{f}$

$v_{f}$ = m1 / (m1 + m2) v₀₁

The initial velocity is calculated in the previous part v₀₁ = v = 0.8 m / s

$v_{f}$ = 100 / (3 + 100) 0.8

$v_{f}$ = 0.777 m / s

c) The change in kinetic energy

Initial K₀ = $K_{f}$

K₀ = 32 J

Final $K_{f}$ = ½ (m1 + m2) $v_{f}$ ²

$K_{f}$ = ½ (3 + 100) 0.777²

$K_{f}$ = 31.07 J

ΔK = $K_{f}$ - K₀

ΔK = 31.07 - 32

ΔK = -0.93 J

As it is a variation it could be given in absolute value

Part D

For this part s has the same initial kinetic energy K = 32 J, but it is block 2 (m2 = 3.00kg) in which it moves

d) we use kinetic energy

v = √ 2K / m2

v = √ (2 32/3)

v = 4.62 m / s

e) the final speed

v₀₂ = v = 4.62 m/s

p₀ = m2 v₀₂

m2 v₀₂ = (m1 + m2) $v_{f}$

$v_{f}$ = m2 / (m1 + m2) v₀₂

$v_{f}$ = 3 / (100 + 3) 4.62

$v_{f}$ = 0.135 m / s

f) variation of kinetic energy

$K_{f}$ = ½ (m1 + m2) $v_{f}$ ²

$K_{f}$ = ½ (3 + 100) 0.135²

$K_{f}$ = 0.9286 J

ΔK = 0.9286-32

ΔK = 31.06 J

4 0

3 years ago