There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here
You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.
Answer:
d=3.67 m
Explanation:
Height of building=46.0 m
First we need to find time taken by egg to reach 1.80 m above the surface
So to find time use below equation
As velocity 1.20m/s is given and we have find time.So we can easily find the distance
So
Initial velocity U = 0
Final velocity V = 32.23 m/s
Explanation:
Given that a coin is dropped from the top of the Tower of Pisa, 53m above the ground.
What is the coin's initial velocity ?
Since the coin is dropped from the tower, the initial velocity U will be equal to zero.
Therefore, U = 0
But the final velocity V will be calculated by using the formula
V^2 = U^2 + 2gH
V^2 = 0 + 2 × 9.8 × 53
V^2 = 1038.8
V = sqrt ( 1038.8)
V = 32.23 m/s
sorry if did not help :(
Answer:
A
Explanation:
because you cannot seperate the matter duhhh hahha
Answer:
The formula of energy is m
. So, energy is M
. Since velocity = displacement/time.
Explanation:
If you have any questions feel free to ask in the comments - Mark
The answer is both.
For kinetic energy:
KE = 1/2*m*v^2 = 0.5*20,000 grams*5 = 50,000 J
For gravitational potential energy:
Pe = mgh = 20,000 grams*9.81 m/s^2*2 m = 392.2 J
