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jolli1 [7]
4 years ago
15

DUE TONIGHT HURRY PLS I give 30 pts

Physics
1 answer:
Paha777 [63]4 years ago
6 0

The answer is both.

For kinetic energy:

KE = 1/2*m*v^2 = 0.5*20,000 grams*5 = 50,000 J

For gravitational potential energy:

Pe = mgh = 20,000 grams*9.81 m/s^2*2 m = 392.2 J      

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Class II levers like ankles and wheelbarrows are useful because they provide mechanical advantage, by amplifying the input force
marusya05 [52]

Answer:

The solution and the explanation are in the Explanation section.

Explanation:

According to the diagram that is in the attached image, the EFFORT force at point A and the load is at O point. The torque due to weight is:

TA = W * (a * cosθ)

The torque due to effort at C point is:

TC = E * (b * cosθ)

The net torque is equal to 0, we have:

Tnet = 0

W * (a * cosθ) - E * (b * cosθ) = 0

E=W\frac{a}{b}

From the figure, you can observe that a/b < 1, thus E < W

8 0
3 years ago
7. En la sala de una casa hay una gran ventana de vidrio, por la que se presenta una pérdida significativa de calor; las medidas
jonny [76]

Answer:

I DON'T SPEAK TACO BELL!

Explanation:

7 0
3 years ago
Calculate potential energy
IrinaVladis [17]
The potential energy of an object is defined by the equation: PE = mgh, where m = the mass of the object, g = the gravitational acceleration and h = the object's height above the ground.
4 0
4 years ago
A non-conducting sphere of radius R = 3.0 cm carries a charge Q = 2.0 mC distributed uniformly throughout its volume. At what di
BlackZzzverrR [31]

Answer:

r =3 *\sqrt{2} = 4.24 cm

Explanation:

given data

Radius of sphere 3.0 cm

charge Q = 2.0 m C

We know that maximum electric field is given as

E_{MAX}= \frac{KQ}{r^{2}}

electric field inside the sphere can be determine by using below relation

\frac{KQ}{r^{2}}= \frac{1}{2}*\frac{KQ}{R^{2}}

r = \sqrt{2}R

r =3 *\sqrt{2} = 4.24 cm

4 0
3 years ago
I have no clue what to do please help.
Yakvenalex [24]

Answer:

Step one : read the directions

Step two: complete the assignment

Explanation:

3 0
2 years ago
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