After reaching the terminal velocity the speed of the oil drop is given as

it drop by 3 mm in 7.33 s


now by the formula of terminal speed




so the radius of drop is 0.16 mm
Now the electric field between the plates is given as


now we will use the condition of equilibrium




so above is the charge on the drop
Answer:
Explanation:
K.E is 1/2 mv^2
Therefore KE is 300000×10000×1/2
=1500000000J
= 1500000KJ
Potential energy is mgh
Therefore PE is 300000×9.8×2000
=5,880,000,000J
=5880000KJ
Answer:
999.23 km/h
Explanation:
We can use the formula for average speed as "Distance divided time" to solve the problem.
Let's start by writing the time in hours: 4 h and 20 min is the same as 4 hours + 1/3 of an hour = 13/3 of an hour
Now we use this number in the quotient for average speed:
Average speed = 4330 km / (13/3) h = 12990 / 30 km/h = 999.23 km/h
-6.7cm just took the time to put this answer down because its been helping me and its right so good luck